Math Problem Statement

Let k be a non-zero constant. The graph of y = kx^2 - 6x + k touches the x-axis at only one point. Are there two possible values for k? Explain your answer.

Solution

We are tasked with analyzing the quadratic equation y=kx26x+ky = kx^2 - 6x + k to determine whether there are two possible values for kk such that the graph of this equation touches the xx-axis at only one point.

Step-by-Step Solution:

  1. Key Condition for Touching the xx-axis:

    • A quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 touches the xx-axis at only one point if it has exactly one real root. This happens when the discriminant (Δ\Delta) of the quadratic equation is zero: Δ=b24ac=0.\Delta = b^2 - 4ac = 0.
  2. Identify the Coefficients: From y=kx26x+ky = kx^2 - 6x + k, the coefficients are: a=k,b=6,c=k.a = k, \quad b = -6, \quad c = k.

  3. Set the Discriminant to Zero: Substitute a=ka = k, b=6b = -6, and c=kc = k into the discriminant formula Δ=b24ac\Delta = b^2 - 4ac: Δ=(6)24(k)(k).\Delta = (-6)^2 - 4(k)(k). Simplify: Δ=364k2.\Delta = 36 - 4k^2. For the graph to touch the xx-axis at one point, set Δ=0\Delta = 0: 364k2=0.36 - 4k^2 = 0.

  4. Solve for kk: Rearrange the equation: 4k2=36.4k^2 = 36. Divide through by 4: k2=9.k^2 = 9. Solve for kk: k=±3.k = \pm 3.

  5. Interpretation:

    • There are two possible values for kk: k=3k = 3 and k=3k = -3.
    • For each of these values, the graph of the equation will touch the xx-axis at exactly one point.

Verification:

For k=3k = 3 and k=3k = -3, substitute back into the equation and confirm:

  • When k=3k = 3, y=3x26x+3y = 3x^2 - 6x + 3. This simplifies to: y=3(x22x+1)=3(x1)2.y = 3(x^2 - 2x + 1) = 3(x - 1)^2. The graph is a parabola with its vertex at (1,0)(1, 0), touching the xx-axis at x=1x = 1.

  • When k=3k = -3, y=3x26x3y = -3x^2 - 6x - 3. This simplifies to: y=3(x2+2x+1)=3(x+1)2.y = -3(x^2 + 2x + 1) = -3(x + 1)^2. The graph is a parabola with its vertex at (1,0)(-1, 0), touching the xx-axis at x=1x = -1.

Final Answer:

Yes, there are two possible values for kk: k=3k = 3 and k=3k = -3.


Would you like further clarification on this solution?

Related Questions:

  1. How do we determine the vertex of a quadratic equation like y=kx26x+ky = kx^2 - 6x + k?
  2. What happens to the graph of the quadratic if Δ>0\Delta > 0 or Δ<0\Delta < 0?
  3. How does the sign of kk affect the direction of the parabola?
  4. Can a quadratic equation touch the xx-axis at more than one point?
  5. How would the problem change if k=0k = 0?

Tip:

Always use the discriminant Δ=b24ac\Delta = b^2 - 4ac to analyze the roots of quadratic equations—it helps quickly determine the nature of the solutions!

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Discriminant Analysis

Formulas

Discriminant formula: Δ = b^2 - 4ac
Quadratic equation: ax^2 + bx + c = 0

Theorems

Discriminant Theorem for Roots of Quadratic Equations

Suitable Grade Level

Grades 9-11