Math Problem Statement

the product of the consecutive integers is 420. which quadratic equation can be used to find x, the lesser number. x^2 +1 =420 x^2 +2 +420 x^2 +x =420 x^2 +2x =420

Solution

The product of two consecutive integers is represented as x(x+1)x(x + 1), where xx is the lesser number.

Given that the product of these integers equals 420, the equation becomes:

x(x+1)=420x(x + 1) = 420

Expanding the left-hand side:

x2+x=420x^2 + x = 420

This corresponds to the quadratic equation x2+x=420x^2 + x = 420.

Thus, the correct equation is:

x2+x=420\boxed{x^2 + x = 420}

Would you like further clarification on this?

Here are 5 related questions:

  1. How do you solve the quadratic equation x2+x=420x^2 + x = 420?
  2. What are consecutive integers, and how do they relate to quadratic equations?
  3. Can a quadratic equation have more than two solutions?
  4. How do you factor quadratic equations like x2+x420=0x^2 + x - 420 = 0?
  5. What are some other real-world examples of quadratic equations?

Tip: When dealing with consecutive numbers, always try to express them as xx and x+1x+1, or xx and x1x-1.

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Math Problem Analysis

Mathematical Concepts

Algebra
Quadratic Equations
Consecutive Integers

Formulas

x(x + 1) = 420
Quadratic equation: ax^2 + bx + c = 0

Theorems

Quadratic formula
Properties of consecutive integers

Suitable Grade Level

Grades 8-10