Math Problem Statement
Solution of 19th
Solution
Let's work through the 19th problem, which asks to prove that for:
we have the following result:
Step-by-step solution:
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Implicit Differentiation of : The expression for involves a complicated function of and , and the goal is to find the second-order partial derivatives and from this.
Let , so . By the chain rule:
where and are the partial derivatives of with respect to and .
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First Derivatives of :
Applying the quotient rule for partial derivatives:
- For :
Simplifying this gives the exact expression for . Similarly, can be calculated by symmetry.
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Second Derivatives:
To get the second-order partial derivatives , apply the product and chain rules again to and .
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Substitute into the Required Expression:
Once you have and , substitute them into the equation:
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Simplify the Result:
After substitution, you'll simplify the expression using trigonometric identities involving . For instance, and will appear from the derivatives of the function, leading to the final result:
This completes the proof.
Would you like further details on any specific step or clarification on the chain rule or quotient rule applications?
Here are 5 related questions:
- How do you compute second-order partial derivatives for complex functions?
- What are the steps in applying Euler's theorem in similar problems?
- How do trigonometric identities help simplify higher-order derivatives?
- Can implicit differentiation be applied to logarithmic or exponential functions similarly?
- What are some common errors to avoid when using the quotient rule in partial differentiation?
Tip: Always simplify your expressions as much as possible before taking higher-order derivatives. It helps prevent errors in the long calculation steps.
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Math Problem Analysis
Mathematical Concepts
Trigonometry
Partial Differentiation
Implicit Differentiation
Chain Rule
Quotient Rule
Formulas
u = tan^{-1} \left( \frac{x^3 + y^3}{\sqrt{x} + \sqrt{y}} \right)
x^2 u_{xx} + 2xy u_{xy} + y^2 u_{yy} = -2 \sin^3(u) \cos(u)
Theorems
Chain Rule for Differentiation
Quotient Rule for Differentiation
Suitable Grade Level
Undergraduate Level - Advanced Calculus
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