Math Problem Statement

Use Euler’s theorem on sin u, and then take the partial derivatives.3. If u = sin−1 s x 1/3 + y 1/3 x 1/2 + y 1/2 , then show that x 2uxx + 2xyuxy + y 2uyy = tan u 12  13 12 + tan2 u 12

Solution

To solve this problem, we need to break it down into several steps:

1. Expression for uu:

The given expression for uu is: u=sin1(x1/3+y1/3x1/2+y1/2)u = \sin^{-1} \left( \frac{x^{1/3} + y^{1/3}}{x^{1/2} + y^{1/2}} \right) This means uu is the inverse sine (arcsine) of the given ratio.

2. Applying Euler's Theorem:

Euler's theorem for sine in terms of complex exponentials is: eiθ=cosθ+isinθe^{i\theta} = \cos\theta + i\sin\theta Thus: sinu=eiueiu2i\sin u = \frac{e^{iu} - e^{-iu}}{2i} However, here we are not directly concerned with expressing sinu\sin u in terms of exponentials, since the question primarily revolves around the derivatives. But Euler’s identity can remind us how trigonometric functions are related to complex exponentials.

3. Implicit Differentiation:

We need to compute second-order partial derivatives of uu with respect to xx and yy.

Let’s define: z=x1/3+y1/3x1/2+y1/2z = \frac{x^{1/3} + y^{1/3}}{x^{1/2} + y^{1/2}} Thus: u=sin1(z)u = \sin^{-1}(z) To find the partial derivatives uxu_x, uyu_y, and second-order partials uxxu_{xx}, uxyu_{xy}, and uyyu_{yy}, we will differentiate uu with respect to xx and yy.

4. First-Order Partial Derivatives:

The chain rule for u=sin1(z)u = \sin^{-1}(z) gives: ux=11z2zxu_x = \frac{1}{\sqrt{1 - z^2}} \cdot z_x uy=11z2zyu_y = \frac{1}{\sqrt{1 - z^2}} \cdot z_y We now need to calculate zxz_x and zyz_y.

5. Second-Order Partial Derivatives:

For the second-order partial derivatives uxxu_{xx}, uxyu_{xy}, and uyyu_{yy}, we apply the product rule and chain rule carefully. For example, for uxxu_{xx}: uxx=x(11z2zx)u_{xx} = \frac{\partial}{\partial x} \left( \frac{1}{\sqrt{1 - z^2}} \cdot z_x \right) This involves taking the derivative of both terms (using the product and chain rules).

6. Substituting into the Original Equation:

The goal is to show that: x2uxx+2xyuxy+y2uyy=tanu12+tan2u12x^2 u_{xx} + 2xy u_{xy} + y^2 u_{yy} = \frac{\tan u}{12} + \frac{\tan^2 u}{12} After calculating the second-order partial derivatives and substituting them into the left-hand side, you should get the required expression.

Summary of Approach:

  • Step 1: Write uu in terms of arcsine and the function zz.
  • Step 2: Use chain rule to find uxu_x and uyu_y.
  • Step 3: Use chain rule and product rule to find second-order derivatives uxxu_{xx}, uxyu_{xy}, and uyyu_{yy}.
  • Step 4: Substitute the second-order partial derivatives into the given equation and simplify to get the desired result.

Would you like a detailed step-by-step calculation for each derivative?

5 Questions:

  1. Would you like to see the full steps for finding uxu_x and uyu_y?
  2. Are you interested in the explicit forms of zxz_x and zyz_y?
  3. Would you like help simplifying the second-order partial derivatives?
  4. Would you like an explanation of how Euler's Theorem is applied here?
  5. Are there other identities you'd like to explore for the arcsine function?

Tip:

When differentiating implicit functions like u=sin1(z)u = \sin^{-1}(z), always remember to apply the chain rule for both first- and second-order derivatives to ensure accurate results.

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Math Problem Analysis

Mathematical Concepts

Partial Derivatives
Trigonometry
Implicit Differentiation

Formulas

Euler’s identity: e^(iθ) = cosθ + i*sinθ
Chain rule for implicit differentiation: du/dx = (du/dz) * (dz/dx)
Inverse sine function: u = sin^(-1)(z)

Theorems

Euler’s Theorem
Chain Rule
Product Rule

Suitable Grade Level

Undergraduate