Math Problem Statement

Show that the permutation group 𝑆ଷ is a group with respect to function composition. How many elements in 𝑆ଷ are of order 2? How many elements are self-invertible?

Solution

1. Showing that S3S_3 is a group with respect to function composition:

The symmetric group S3S_3 is the group of all permutations of three elements, say {1,2,3}\{1, 2, 3\}. To show that S3S_3 is a group with respect to function composition, we need to check if it satisfies the four group axioms:

  • Closure: For any two elements Οƒ\sigma and Ο„\tau in S3S_3, their composition Οƒβˆ˜Ο„\sigma \circ \tau must also be in S3S_3. Since function composition of permutations is another permutation, closure holds.

  • Associativity: Function composition is associative by definition. That is, for any Οƒ,Ο„,ρ∈S3\sigma, \tau, \rho \in S_3, we have (Οƒβˆ˜Ο„)∘ρ=Οƒβˆ˜(Ο„βˆ˜Ο)(\sigma \circ \tau) \circ \rho = \sigma \circ (\tau \circ \rho).

  • Identity element: The identity element in S3S_3 is the identity permutation e=(1)(2)(3)e = (1)(2)(3), which maps each element to itself. For any permutation ΟƒβˆˆS3\sigma \in S_3, we have Οƒβˆ˜e=eβˆ˜Οƒ=Οƒ\sigma \circ e = e \circ \sigma = \sigma.

  • Inverses: For every element ΟƒβˆˆS3\sigma \in S_3, there exists an inverse element Οƒβˆ’1∈S3\sigma^{-1} \in S_3 such that Οƒβˆ˜Οƒβˆ’1=Οƒβˆ’1βˆ˜Οƒ=e\sigma \circ \sigma^{-1} = \sigma^{-1} \circ \sigma = e.

Thus, S3S_3 satisfies all the group axioms, and therefore it is a group under function composition.

2. Number of elements in S3S_3 of order 2:

The order of an element ΟƒβˆˆS3\sigma \in S_3 is the smallest integer kk such that Οƒk=e\sigma^k = e, where ee is the identity permutation.

The elements of S3S_3 are:

  1. e=(1)(2)(3)e = (1)(2)(3) β€” identity
  2. (12)(12) β€” transposition swapping 1 and 2
  3. (13)(13) β€” transposition swapping 1 and 3
  4. (23)(23) β€” transposition swapping 2 and 3
  5. (123)(123) β€” cyclic permutation: 1 β†’ 2, 2 β†’ 3, 3 β†’ 1
  6. (132)(132) β€” cyclic permutation: 1 β†’ 3, 3 β†’ 2, 2 β†’ 1

Now, we find the order of each element:

  • ee: order 1 (since e1=ee^1 = e).
  • (12),(13),(23)(12), (13), (23): These are transpositions, and each of them squares to the identity: (12)2=e(12)^2 = e, (13)2=e(13)^2 = e, (23)2=e(23)^2 = e. Hence, their order is 2.
  • (123),(132)(123), (132): These are 3-cycles, and their order is 3 because (123)3=e(123)^3 = e and (132)3=e(132)^3 = e.

Thus, there are 3 elements of order 2: (12),(13),(23)(12), (13), (23).

3. Number of self-invertible elements in S3S_3:

An element ΟƒβˆˆS3\sigma \in S_3 is self-invertible if Οƒ=Οƒβˆ’1\sigma = \sigma^{-1}. This is true if Οƒ2=e\sigma^2 = e. Therefore, the self-invertible elements are those of order 1 or 2.

  • The identity ee is trivially self-invertible.
  • The elements (12),(13),(23)(12), (13), (23), all of order 2, are also self-invertible.

Thus, there are 4 self-invertible elements in S3S_3: e,(12),(13),(23)e, (12), (13), (23).

Summary:

  • S3S_3 is a group under function composition.
  • There are 3 elements in S3S_3 of order 2: (12),(13),(23)(12), (13), (23).
  • There are 4 self-invertible elements in S3S_3: e,(12),(13),(23)e, (12), (13), (23).

Would you like further details or clarification?

Here are some related questions:

  1. What is the general structure of SnS_n, the symmetric group on nn elements?
  2. Can you explain why every transposition is of order 2 in any SnS_n?
  3. How does the number of elements of each order vary as nn increases in SnS_n?
  4. What is the significance of self-invertible elements in group theory?
  5. Can you describe the concept of conjugacy classes in S3S_3?

Tip: In symmetric groups, transpositions are always of order 2, while cycles of length kk have order kk.

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Math Problem Analysis

Mathematical Concepts

Group Theory
Symmetric Groups
Permutation Groups
Function Composition
Order of Elements

Formulas

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Theorems

Group Axioms: Closure, Associativity, Identity, Inverses

Suitable Grade Level

Undergraduate Mathematics