Math Problem Statement

S_3 direct sum A_3/ Z(S_3+ A_3) is isomorphic to which group

Solution

Let's analyze the expression S3A3/Z(S3A3)S_3 \oplus A_3 / Z(S_3 \oplus A_3) to determine which group it is isomorphic to.

Step 1: Understanding the groups involved

  • S3S_3 is the symmetric group of degree 3, which consists of all permutations of 3 elements. It has 6 elements: S3={e,(12),(13),(23),(123),(132)}S_3 = \{ e, (12), (13), (23), (123), (132) \}

  • A3A_3 is the alternating group of degree 3, which is the group of even permutations in S3S_3. It has 3 elements: A3={e,(123),(132)}A_3 = \{ e, (123), (132) \} This is isomorphic to the cyclic group Z3\mathbb{Z}_3.

  • The direct sum S3A3S_3 \oplus A_3 consists of ordered pairs where the first element comes from S3S_3 and the second from A3A_3. This group will have 6×3=186 \times 3 = 18 elements.

Step 2: Understanding the center Z(S3A3)Z(S_3 \oplus A_3)

The center Z(G)Z(G) of a group GG consists of all elements that commute with every element of the group.

  • For S3S_3, the center is trivial: Z(S3)={e}Z(S_3) = \{ e \}, because no non-identity element in S3S_3 commutes with all others.
  • For A3A_3, the center is also trivial: Z(A3)={e}Z(A_3) = \{ e \}, since A3A_3 is isomorphic to Z3\mathbb{Z}_3, a simple group.

Thus, the center of the direct sum S3A3S_3 \oplus A_3 is also trivial: Z(S3A3)={(e,e)}Z(S_3 \oplus A_3) = \{(e, e)\}

Step 3: Simplifying the quotient

The quotient S3A3/Z(S3A3)S_3 \oplus A_3 / Z(S_3 \oplus A_3) is essentially the group S3A3S_3 \oplus A_3 itself, since the center is trivial: S3A3/Z(S3A3)S3A3S_3 \oplus A_3 / Z(S_3 \oplus A_3) \cong S_3 \oplus A_3

Step 4: Isomorphism

We now check what S3A3S_3 \oplus A_3 is isomorphic to. Since A3Z3A_3 \cong \mathbb{Z}_3, we have: S3A3S3Z3S_3 \oplus A_3 \cong S_3 \oplus \mathbb{Z}_3

This is a direct sum of the symmetric group S3S_3 and the cyclic group Z3\mathbb{Z}_3. There is no further simplification in terms of common small groups, so the group is isomorphic to S3Z3S_3 \oplus \mathbb{Z}_3.

Conclusion

S3A3/Z(S3A3)S3Z3S_3 \oplus A_3 / Z(S_3 \oplus A_3) \cong S_3 \oplus \mathbb{Z}_3

This is the final isomorphic group.

Would you like more details or further clarification?

Related questions:

  1. What are the properties of the center of a group?
  2. Can the direct product of S3S_3 and A3A_3 be simplified further?
  3. How do you find the center of other common groups like SnS_n?
  4. What is the structure of SnS_n for n>3n > 3?
  5. How does S3S_3 compare to other symmetric groups?

Tip:

In group theory, quotienting by the center of a group gives the inner automorphism group, revealing how elements interact via conjugation.

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Math Problem Analysis

Mathematical Concepts

Group Theory
Symmetric Groups
Alternating Groups
Direct Sum
Quotient Groups
Group Isomorphisms

Formulas

S_3 = {e, (12), (13), (23), (123), (132)}
A_3 = {e, (123), (132)}
Z(S_3) = {e}
Z(A_3) = {e}
Z(S_3 ⊕ A_3) = {(e, e)}
S_3 ⊕ A_3 / Z(S_3 ⊕ A_3) ≅ S_3 ⊕ A_3

Theorems

Direct Sum of Groups
Center of a Group
Group Isomorphism Theorem

Suitable Grade Level

University Level (Abstract Algebra)