Math Problem Statement

using formal mathematical logical deduction, prove ∀ϵ ∈ N, (ϵ + 1)^3 − 5ϵ^2 + 6 is odd

Solution

To prove that the expression (ϵ+1)35ϵ2+6(\epsilon + 1)^3 - 5\epsilon^2 + 6 is odd for all ϵN\epsilon \in \mathbb{N} (the set of natural numbers), we will use formal mathematical deduction.

Step-by-Step Proof

  1. Expression Analysis:
    Consider the expression: f(ϵ)=(ϵ+1)35ϵ2+6.f(\epsilon) = (\epsilon + 1)^3 - 5\epsilon^2 + 6.

  2. Expand the Cubic Term:
    Start by expanding (ϵ+1)3(\epsilon + 1)^3: (ϵ+1)3=ϵ3+3ϵ2+3ϵ+1.(\epsilon + 1)^3 = \epsilon^3 + 3\epsilon^2 + 3\epsilon + 1.

  3. Substitute and Simplify:
    Substitute the expanded term into the expression: f(ϵ)=(ϵ3+3ϵ2+3ϵ+1)5ϵ2+6.f(\epsilon) = (\epsilon^3 + 3\epsilon^2 + 3\epsilon + 1) - 5\epsilon^2 + 6. Simplify the expression by combining like terms: f(ϵ)=ϵ32ϵ2+3ϵ+7.f(\epsilon) = \epsilon^3 - 2\epsilon^2 + 3\epsilon + 7.

  4. Determine the Parity of f(ϵ)f(\epsilon):
    To determine if f(ϵ)f(\epsilon) is odd, we need to show that f(ϵ)mod2=1f(\epsilon) \mod 2 = 1.

    Evaluate each term modulo 2:

    • ϵ3mod2=ϵmod2\epsilon^3 \mod 2 = \epsilon \mod 2 (since the cube of an integer has the same parity as the integer itself).
    • 2ϵ2mod2=02\epsilon^2 \mod 2 = 0 (since 2ϵ22\epsilon^2 is always even).
    • 3ϵmod2=(1ϵ)mod2=ϵmod23\epsilon \mod 2 = (1\epsilon) \mod 2 = \epsilon \mod 2 (since 31(mod2)3 \equiv 1 \pmod{2}).
    • 7mod2=17 \mod 2 = 1 (since 7 is odd).

    Substitute these into the expression: f(ϵ)(ϵ0+ϵ+1)mod2.f(\epsilon) \equiv (\epsilon - 0 + \epsilon + 1) \mod 2. Simplify: f(ϵ)(2ϵ+1)mod2.f(\epsilon) \equiv (2\epsilon + 1) \mod 2.

  5. Conclude the Parity:
    Since 2ϵmod2=02\epsilon \mod 2 = 0, we have: f(ϵ)0+11mod2.f(\epsilon) \equiv 0 + 1 \equiv 1 \mod 2.

    Therefore, f(ϵ)f(\epsilon) is odd for all ϵN\epsilon \in \mathbb{N}.

Conclusion

We have shown that (ϵ+1)35ϵ2+6(\epsilon + 1)^3 - 5\epsilon^2 + 6 is odd for all ϵN\epsilon \in \mathbb{N} using formal logical deduction and properties of congruences.

Would you like more details on any part of the proof, or do you have any other questions?

Here are 5 related questions that might interest you:

  1. How do we prove the parity of a polynomial function in general?
  2. What is the significance of modular arithmetic in number theory?
  3. How can we extend this method to prove properties of more complex expressions?
  4. Can this technique be used to prove properties for expressions over other domains (e.g., integers)?
  5. What is the relevance of proving properties for all natural numbers in mathematical logic?

Tip: When proving properties involving parity (odd or even), modular arithmetic is a powerful tool to simplify calculations!

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Math Problem Analysis

Mathematical Concepts

Algebra
Number Theory
Modular Arithmetic
Polynomials

Formulas

(ϵ + 1)^3 = ϵ^3 + 3ϵ^2 + 3ϵ + 1
f(ϵ) = (ϵ + 1)^3 - 5ϵ^2 + 6
f(ϵ) mod 2 = (2ϵ + 1) mod 2

Theorems

Properties of Odd and Even Numbers
Modular Arithmetic Theorem

Suitable Grade Level

Grades 9-12