Math Problem Statement

Exercise 2. Let’s prove the triangle inequality algebraically! For this problem, you

may find it useful to use Exercise 10.3 from the sheet.

(a) Given v, w ∈ C, show that |z + w|2 = |z|2 + |w|2 + 2Re(z ¯w).

Solution

To prove the given equation algebraically, we start with the left-hand side of the equation and simplify it using properties of complex numbers.

Problem: Show that for v,wCv, w \in \mathbb{C},

z+w2=z2+w2+2Re(zw).|z + w|^2 = |z|^2 + |w|^2 + 2\text{Re}(z \overline{w}).


Proof:

  1. Start with the definition of the modulus squared: The modulus squared of a complex number is given by: z+w2=(z+w)(z+w).|z + w|^2 = (z + w)(\overline{z + w}).

  2. Expand using distributive property: Substitute z+w=z+w\overline{z + w} = \overline{z} + \overline{w}: z+w2=(z+w)(z+w).|z + w|^2 = (z + w)(\overline{z} + \overline{w}).

  3. Multiply out the terms: Expand the product: z+w2=zz+zw+wz+ww.|z + w|^2 = z\overline{z} + z\overline{w} + w\overline{z} + w\overline{w}.

  4. Group the terms: Recognize that zz=z2z\overline{z} = |z|^2 and ww=w2w\overline{w} = |w|^2. So: z+w2=z2+w2+(zw+wz).|z + w|^2 = |z|^2 + |w|^2 + (z\overline{w} + w\overline{z}).

  5. Simplify using the real part: Recall that for any complex number aa, a+a=2Re(a)a + \overline{a} = 2\text{Re}(a). Here, zw+wzz\overline{w} + w\overline{z} is the sum of a complex number and its conjugate, so: zw+wz=2Re(zw).z\overline{w} + w\overline{z} = 2\text{Re}(z\overline{w}).

  6. Combine the results: Substitute this back into the equation: z+w2=z2+w2+2Re(zw).|z + w|^2 = |z|^2 + |w|^2 + 2\text{Re}(z\overline{w}).

Thus, we have shown that: z+w2=z2+w2+2Re(zw).|z + w|^2 = |z|^2 + |w|^2 + 2\text{Re}(z\overline{w}).


Explanation:

The key steps involve:

  1. Expanding the definition of the modulus squared.
  2. Using the property of the conjugate and the distributive law.
  3. Simplifying the result by identifying the real part.

Let me know if you'd like further clarifications on any step!


Follow-Up Questions:

  1. What is the geometric interpretation of z2|z|^2 for a complex number zz?
  2. How does the real part 2Re(zw)2\text{Re}(z\overline{w}) affect the value of z+w2|z + w|^2?
  3. What properties of conjugates were used in the proof?
  4. How does this result connect to the triangle inequality in complex analysis?
  5. Can this formula be extended to vectors in higher dimensions?

Tip:

Remember that the modulus z|z| of a complex number represents its distance from the origin in the complex plane.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Modulus of Complex Numbers
Real and Imaginary Parts
Algebraic Expansion

Formulas

|z + w|^2 = (z + w)(overline{z + w})
Re(a) = (a + overline{a}) / 2
|z|^2 = z * overline{z}

Theorems

Triangle Inequality for Complex Numbers
Properties of Complex Conjugates

Suitable Grade Level

Grades 11-12 or Undergraduate