Math Problem Statement
Exercise 2. Let’s prove the triangle inequality algebraically! For this problem, you
may find it useful to use Exercise 10.3 from the sheet.
(a) Given v, w ∈ C, show that |z + w|2 = |z|2 + |w|2 + 2Re(z ¯w).
Solution
To prove the given equation algebraically, we start with the left-hand side of the equation and simplify it using properties of complex numbers.
Problem: Show that for ,
Proof:
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Start with the definition of the modulus squared: The modulus squared of a complex number is given by:
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Expand using distributive property: Substitute :
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Multiply out the terms: Expand the product:
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Group the terms: Recognize that and . So:
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Simplify using the real part: Recall that for any complex number , . Here, is the sum of a complex number and its conjugate, so:
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Combine the results: Substitute this back into the equation:
Thus, we have shown that:
Explanation:
The key steps involve:
- Expanding the definition of the modulus squared.
- Using the property of the conjugate and the distributive law.
- Simplifying the result by identifying the real part.
Let me know if you'd like further clarifications on any step!
Follow-Up Questions:
- What is the geometric interpretation of for a complex number ?
- How does the real part affect the value of ?
- What properties of conjugates were used in the proof?
- How does this result connect to the triangle inequality in complex analysis?
- Can this formula be extended to vectors in higher dimensions?
Tip:
Remember that the modulus of a complex number represents its distance from the origin in the complex plane.
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Math Problem Analysis
Mathematical Concepts
Complex Numbers
Modulus of Complex Numbers
Real and Imaginary Parts
Algebraic Expansion
Formulas
|z + w|^2 = (z + w)(overline{z + w})
Re(a) = (a + overline{a}) / 2
|z|^2 = z * overline{z}
Theorems
Triangle Inequality for Complex Numbers
Properties of Complex Conjugates
Suitable Grade Level
Grades 11-12 or Undergraduate
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