Math Problem Statement
Prove that if n is any positive integer, then+is irrational.
Solution
To prove that is irrational for any positive integer that is not a perfect square, we can use a proof by contradiction. Here's how the proof goes:
Proof by Contradiction:
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Assume the opposite: Suppose is rational for some positive integer , but is not a perfect square.
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Express as a fraction: Since is rational, it can be expressed as: where and are integers with no common factors other than 1 (i.e., the fraction is in its lowest terms), and .
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Square both sides to remove the square root:
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Rearrange the equation to: This equation states that is equal to multiplied by .
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Analyze the implications: Since is a perfect square, must also be a perfect square. For to be a perfect square, itself must be a perfect square because is already a perfect square.
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Contradiction: However, we assumed that is not a perfect square. Therefore, this implies that cannot be a perfect square, which contradicts the requirement that must be a perfect square.
Conclusion:
Since our assumption that is rational leads to a contradiction, the original assumption must be false. Therefore, must be irrational if is not a perfect square.
Would you like more details or have any questions? Here are some related questions you might find interesting:
- What is an example of a number that is a perfect square, and why is rational in this case?
- How can you prove the irrationality of using a similar method?
- What are some other common irrational numbers, and how can their irrationality be proven?
- Can you describe the difference between rational and irrational numbers?
- How would the proof change if were a negative integer?
Tip: When dealing with proofs by contradiction, it's essential to carefully examine the logical steps that lead to a contradiction to ensure the proof's validity.
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Math Problem Analysis
Mathematical Concepts
Irrational Numbers
Proof by Contradiction
Square Roots
Formulas
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Theorems
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Suitable Grade Level
Advanced High School and College