Math Problem Statement
Solution
The task in the image asks to prove that the interval is not countable. Here's a structured proof of that statement using Cantor's diagonalization argument.
Proof (Cantor's Diagonalization Argument):
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Assume for contradiction: Suppose the interval is countable. This would mean we can list all the real numbers in this interval as a sequence: where each is a real number in , and every real number in this interval appears somewhere on this list.
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Decimal expansion: Write each number in its decimal expansion. That is, for each , we represent it as: where represents the -th decimal digit of the -th number.
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Construct a new number: We now construct a new number in the interval , which is not in the list. Define by choosing its decimal digits as follows:
- Let be different from .
- Let be different from .
- Let be different from , and so on.
More formally, for each , choose , ensuring that differs from each in at least the -th decimal place.
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Contradiction: The number cannot be on the list, because it differs from in the first decimal place, from in the second decimal place, and so on. This contradicts the assumption that all real numbers in are listed.
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Conclusion: Therefore, the interval is uncountable.
Would you like further details or have any questions about this proof? Here are some related questions to deepen understanding:
- What does it mean for a set to be countable?
- Can the set of rational numbers in be counted, and how?
- How does Cantor's diagonalization argument apply to other infinite sets?
- What is the difference between countably infinite and uncountably infinite sets?
- Can you apply diagonalization to other intervals, such as ?
Tip: The essence of Cantor's diagonalization is creating something new by ensuring it differs at least in one position from every item in a list.
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Math Problem Analysis
Mathematical Concepts
Real Analysis
Set Theory
Countability
Uncountable Sets
Formulas
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Theorems
Cantor's Diagonalization Argument
Suitable Grade Level
College/University Level
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