Math Problem Statement
Solution
The question asks to "Prove that the interval is not countable."
Here’s a proof using Cantor's Diagonalization Argument, a classic method to show that the interval is uncountable:
Proof:
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Assume for contradiction that the interval is countable. This means that the real numbers in can be listed in a sequence .
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Each number in the interval can be represented by its decimal expansion: Where represents the -th digit of the -th number.
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Construct a new number where each digit is chosen such that is different from the -th digit of . For example, let:
1 & \text{if } a_{ii} \neq 1 \\ 2 & \text{if } a_{ii} = 1 \end{cases}$$ This ensures that $$y$$ is not equal to $$x_i$$ for any $$i$$, because $$y$$ differs from each $$x_i$$ at least in the $$i$$-th decimal place. -
Since differs from every number in the supposed list, is a real number in that is not in the list .
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This is a contradiction because we assumed that all numbers in were listed.
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Therefore, the interval cannot be countable. Hence, is uncountable.
This proof shows that it is impossible to form a one-to-one correspondence between the real numbers in and the natural numbers, implying that is uncountable.
Would you like further clarification or details on this proof?
Related Questions:
- What is the difference between countable and uncountable sets?
- How does Cantor's diagonalization work for proving other sets are uncountable?
- Can you provide examples of countable sets besides the natural numbers?
- What are some practical implications of uncountable sets in mathematics?
- How does the cardinality of the interval compare to the set of real numbers?
Tip:
When dealing with infinite sets, Cantor's diagonalization is a powerful method to demonstrate uncountability.
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Math Problem Analysis
Mathematical Concepts
Set Theory
Real Numbers
Infinity
Formulas
-
Theorems
Cantor's Diagonalization Argument
Suitable Grade Level
University Level
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