Math Problem Statement
Solution
The question asks us to prove that , where:
- is the group of all matrices with real entries under matrix addition.
- is the subset of consisting of matrices of the form: where .
To show that , we need to prove that is a subgroup of . We will do this by checking the subgroup criteria:
- Closure under addition: If , then .
- Existence of an identity element: The zero matrix should be in .
- Existence of inverses: For each , the additive inverse should also be in .
Let's go through each condition.
Step 1: Closure under addition
Suppose and are elements of . This means: Now, consider .
For to be in , it must satisfy . Notice that: Thus, , showing closure under addition.
Step 2: Identity element
The identity element in under addition is the zero matrix . Since , the zero matrix satisfies and therefore belongs to .
Step 3: Existence of inverses
For , consider its additive inverse . Since , we have: Thus, , so every element in has an additive inverse in .
Conclusion
Since is closed under addition, contains the identity element, and contains inverses, is a subgroup of . Therefore, we have shown that .
Would you like further clarification on any step?
Related Questions
- What is the difference between a group and a subgroup?
- How can we verify the subgroup criteria in general for matrix groups?
- What are other examples of conditions that can define subgroups of matrix groups?
- Can the same method be applied to prove subgroup properties in groups other than matrices?
- What is the significance of additive and multiplicative subgroups in linear algebra?
Tip
Remember, to prove a subset is a subgroup, verifying closure, identity, and inverses with respect to the group's operation is key.
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Math Problem Analysis
Mathematical Concepts
Abstract Algebra
Matrix Groups
Subgroup Criterion
Formulas
Matrix addition
Subgroup criteria
Theorems
Subgroup Test
Suitable Grade Level
College Level (Abstract Algebra)