Math Problem Statement
prove the following theorem : When it exists, the limit of a sequence is unique
Solution
Theorem: When it exists, the limit of a sequence is unique.
Proof:
Let be a sequence, and suppose that this sequence converges to two distinct limits. Specifically, let:
We aim to show that , thus proving that the limit, if it exists, is unique.
Step 1: Definition of Limit
By the definition of a limit of a sequence, we know:
- Since , for every , there exists an integer such that for all , we have:
- Similarly, since , for every , there exists an integer such that for all , we have:
Step 2: Choose an Arbitrary
Now, let's consider an arbitrary positive number . We need to show that .
Step 3: Choose
Since both and exist, we can choose , which means that for all :
Step 4: Use the Triangle Inequality
Now, consider the absolute difference between and :
By the triangle inequality, we have:
For , we know that both and . Therefore:
Step 5: Conclusion
Since is arbitrary, we can make it as small as we like. This implies that:
Thus, , which shows that the limit of a sequence, when it exists, is unique.
Final Conclusion:
We have proven that the limit of a sequence, when it exists, must be unique.
Would you like any more details or clarifications? Here are some related questions you might find useful:
- What is the formal definition of the limit of a sequence?
- Can a sequence have more than one limit? Under what conditions?
- How do the concepts of convergence and boundedness relate in sequences?
- What happens if a sequence does not converge?
- What is the difference between a limit point and a limit of a sequence?
Tip: Always remember that in the context of sequences, the limit is only defined if the terms of the sequence get arbitrarily close to a specific value as . If they oscillate or fail to approach any particular value, the limit doesn't exist.
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Math Problem Analysis
Mathematical Concepts
Sequence Convergence
Limits of Sequences
Proof by Contradiction
Triangle Inequality
Formulas
|a_n - L_1| < epsilon
|a_n - L_2| < epsilon
|L_1 - L_2| <= |L_1 - a_n| + |a_n - L_2|
Theorems
Uniqueness of Limit for Sequences
Suitable Grade Level
Grades 11-12 (Advanced)