Math Problem Statement

Show that if (an)n∈N,(bn)n∈N are equivalent sequences, then (an)n∈N converges if and only if (bn)n∈N converges

Solution

To show that if (an)nN(a_n)_{n \in \mathbb{N}} and (bn)nN(b_n)_{n \in \mathbb{N}} are equivalent sequences, then (an)nN(a_n)_{n \in \mathbb{N}} converges if and only if (bn)nN(b_n)_{n \in \mathbb{N}} converges, we need to first understand the definition of equivalent sequences.

Definition of Equivalent Sequences:

Two sequences (an)(a_n) and (bn)(b_n) are said to be equivalent if:

limn(anbn)=0\lim_{n \to \infty} (a_n - b_n) = 0

This means that as nn becomes arbitrarily large, the difference between ana_n and bnb_n becomes arbitrarily small.

Proof:

We will show both directions of the statement.

1. If (an)(a_n) converges, then (bn)(b_n) converges:

Let (an)(a_n) converge to some limit LRL \in \mathbb{R}, i.e.,

limnan=L.\lim_{n \to \infty} a_n = L.

We are also given that (an)(a_n) and (bn)(b_n) are equivalent, which implies:

limn(anbn)=0.\lim_{n \to \infty} (a_n - b_n) = 0.

Thus, we can rewrite bnb_n as:

bn=an(anbn).b_n = a_n - (a_n - b_n).

Now, since limnan=L\lim_{n \to \infty} a_n = L and limn(anbn)=0\lim_{n \to \infty} (a_n - b_n) = 0, by the sum of limits property, we have:

limnbn=limnanlimn(anbn)=L0=L.\lim_{n \to \infty} b_n = \lim_{n \to \infty} a_n - \lim_{n \to \infty} (a_n - b_n) = L - 0 = L.

Thus, (bn)(b_n) converges to LL.

2. If (bn)(b_n) converges, then (an)(a_n) converges:

Let (bn)(b_n) converge to some limit LRL \in \mathbb{R}, i.e.,

limnbn=L.\lim_{n \to \infty} b_n = L.

Since (an)(a_n) and (bn)(b_n) are equivalent, we again know:

limn(anbn)=0.\lim_{n \to \infty} (a_n - b_n) = 0.

Now, we can rewrite ana_n as:

an=bn+(anbn).a_n = b_n + (a_n - b_n).

Using the sum of limits property again, we have:

limnan=limnbn+limn(anbn)=L+0=L.\lim_{n \to \infty} a_n = \lim_{n \to \infty} b_n + \lim_{n \to \infty} (a_n - b_n) = L + 0 = L.

Thus, (an)(a_n) converges to LL.

Conclusion:

Since we've shown both directions, we conclude that:

(an)nN converges if and only if (bn)nN converges.(a_n)_{n \in \mathbb{N}} \text{ converges if and only if } (b_n)_{n \in \mathbb{N}} \text{ converges}.

Would you like more details or have any questions?

Here are 5 related questions:

  1. How do we define the convergence of a sequence rigorously?
  2. Can you give examples of two equivalent sequences?
  3. What is the sum of limits property used in the proof?
  4. How can we visualize the concept of equivalent sequences?
  5. Does the proof hold if the sequences are complex-valued instead of real-valued?

Tip: Equivalent sequences must get arbitrarily close as nn grows large, but they don't need to be identical at every step.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Convergence of sequences
Equivalent sequences
Limits

Formulas

lim_{n -> ∞} (an - bn) = 0
lim_{n -> ∞} an = L
lim_{n -> ∞} bn = L

Theorems

Sum of limits property
Definition of equivalent sequences

Suitable Grade Level

Undergraduate (First-year calculus or analysis)