Math Problem Statement

设 f(x) : [a, b] → ℝ 是连续可微函数,且 ∫_a^b f(x) dx = 0,求证: ( ∫_a^{2b-a} f(x) dx )^2 ≤ (2(b-a)^3/3) ∫_a^{2b} (f'(x))^2 dx

Solution

The question in the image is a mathematical proof problem. It involves proving an inequality related to an integral function. Here's the summary:

We are given a continuous and differentiable function f(x)f(x) on the interval [a,b][a, b], with the condition:

abf(x)dx=0\int_a^b f(x) \, dx = 0

We need to prove the inequality:

(a2baf(x)dx)22(ba)33a2b(f(x))2dx\left( \int_a^{2b-a} f(x) \, dx \right)^2 \leq \frac{2(b - a)^3}{3} \int_a^{2b} (f'(x))^2 \, dx

This appears to be a problem that combines integral calculus with inequality proving. The method of solution could involve the application of certain integral inequalities, possibly related to the Cauchy-Schwarz inequality or integration by parts.

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Math Problem Analysis

Mathematical Concepts

Integral Calculus
Differentiability
Inequality Proofs

Formulas

∫_a^b f(x) dx = 0
( ∫_a^{2b-a} f(x) dx )^2 ≤ (2(b-a)^3/3) ∫_a^{2b} (f'(x))^2 dx

Theorems

Cauchy-Schwarz Inequality
Integration by Parts

Suitable Grade Level

Advanced Undergraduate/Graduate