Math Problem Statement

A ball is thrown horizontally from the top of a 20-m high hill. It strikes the ground at an angle of 45°. With what speed was it thrown? Use g = 10 m/s².

Solution

To solve this problem, we can break it down into two components: the horizontal motion and the vertical motion of the ball.

Step 1: Analyze the Vertical Motion

The ball is thrown horizontally, so initially, it has no vertical velocity. The only vertical motion comes from the acceleration due to gravity, g=10m/s2g = 10 \, \text{m/s}^2.

Using the equation of motion for vertical displacement: h=12gt2h = \frac{1}{2} g t^2 where:

  • h=20mh = 20 \, \text{m} (height of the hill)
  • g=10m/s2g = 10 \, \text{m/s}^2 (acceleration due to gravity)
  • tt is the time of flight

Rearranging to solve for tt: t=2hg=2×2010=4=2secondst = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2 \times 20}{10}} = \sqrt{4} = 2 \, \text{seconds}

Step 2: Analyze the Horizontal Motion

Since the ball is thrown horizontally, its horizontal velocity uxu_x remains constant throughout the motion. We know that the horizontal velocity uxu_x can be related to the total velocity uu and the angle of impact (45° in this case).

The horizontal and vertical components of the velocity at the point of impact are equal because the angle of impact is 45°: ux=uyu_x = u_y where uyu_y is the vertical velocity at the moment of impact.

Step 3: Calculate the Vertical Velocity at Impact

The vertical velocity at impact uyu_y can be found using the equation: uy=gt=10m/s2×2seconds=20m/su_y = g \cdot t = 10 \, \text{m/s}^2 \times 2 \, \text{seconds} = 20 \, \text{m/s}

Step 4: Determine the Horizontal Velocity (Initial Speed)

Since ux=uyu_x = u_y at the point of impact, we have: ux=20m/su_x = 20 \, \text{m/s}

This uxu_x is the speed with which the ball was thrown, so the ball was thrown with a speed of 20m/s20 \, \text{m/s}.

Would you like more details or have any questions about the solution?

Here are five related questions to further your understanding:

  1. What would be the speed of the ball if it were thrown from a different height?
  2. How would the impact angle change if the ball was thrown with an initial upward velocity?
  3. What is the range of the ball's horizontal displacement from the point of release to where it strikes the ground?
  4. How would air resistance affect the time of flight and the impact velocity?
  5. If the ball was thrown from a moving platform, how would the platform's velocity affect the ball's trajectory?

Tip: When analyzing projectile motion, always break the motion into horizontal and vertical components to simplify your calculations.

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Math Problem Analysis

Mathematical Concepts

Projectile Motion
Kinematics
Trigonometry

Formulas

h = (1/2) * g * t^2
t = sqrt(2h/g)
v_y = g * t
v_x = v_y (at impact angle of 45°)

Theorems

Equations of Motion
Trigonometric Relationships in Right-Angle Triangles

Suitable Grade Level

Grades 9-12