Sure, let's denote the events as follows to clarify and solve for the probabilities:

1. $P(A \cup D)$
2. $P(E \cup B)$
3. $P(D \cup E)$
4. $P(C \cup F)$

1. $P(A \cup D)$

Using the formula for the probability of the union of two events: $P(A \cup D) = P(A) + P(D) - P(A \cap D)$

2. $P(E \cup B)$

Using the same formula: $P(E \cup B) = P(E) + P(B) - P(E \cap B)$

3. $P(D \cup E)$

Similarly: $P(D \cup E) = P(D) + P(E) - P(D \cap E)$

4. $P(C \cup F)$

And for the last one: $P(C \cup F) = P(C) + P(F) - P(C \cap F)$

Steps to Calculate

1. Identify the individual probabilities: $P(A), P(D), P(E), P(B), P(C), P(F)$
2. Identify the intersection probabilities: $P(A \cap D), P(E \cap B), P(D \cap E), P(C \cap F)$
3. Apply the formula: Substitute these values into the union probability formula.

Please provide the specific probabilities of these events and their intersections so I can compute the exact values for you.

---

Do you want detailed explanations or have any questions about the process? Here are some related questions that might help expand your understanding:

1. How do you calculate the intersection of two probabilities?
2. What is the difference between union and intersection in probability?
3. How does the principle of inclusion-exclusion apply to probability?
4. Can you explain with a Venn diagram how the union of two events is calculated?
5. How would the formulas change if the events were mutually exclusive?

Tip: Remember that for mutually exclusive events, the intersection probability $P(A \cap B)$ is zero, simplifying the union formula to $P(A \cup B) = P(A) + P(B)$.