Math Problem Statement

If E and F are not disjoint​ events, then​ P(E or ​F)equals​________.

Solution

If EE and FF are not disjoint events, the probability of EE or FF occurring is given by the Inclusion-Exclusion Principle. The formula is:

P(EF)=P(E)+P(F)P(EF)P(E \cup F) = P(E) + P(F) - P(E \cap F)

So, the probability P(E or F)P(E \text{ or } F) equals P(E)+P(F)P(EF)P(E) + P(F) - P(E \cap F).

This formula adjusts for the fact that EE and FF might overlap (i.e., both events could happen at the same time), so we subtract the probability of their intersection to avoid double-counting.

Would you like further details or have any other questions?

Here are 5 related questions:

  1. How do you calculate P(EF)P(E \cap F) if EE and FF are independent events?
  2. What is the formula for P(EF)P(E \cup F) if EE and FF are mutually exclusive?
  3. How does the inclusion-exclusion principle extend to three or more events?
  4. What does it mean for events to be disjoint?
  5. Can you explain why we subtract P(EF)P(E \cap F) in the formula?

Tip: When solving probability problems, always check if events are independent, mutually exclusive, or neither. This helps determine the correct formula to use.