Math Problem Statement

Activity 4: Taking Chances with Events A or B. Consider the situations below and answer the questions that follow. 1. A bowl contains 15 chips numbered 1 to 15. If a chip is drawn randomly from the bowl, what is the probability that it is: a) 7 or 15? b) 5 or a number divisible by 3? c) even or divisible by 3? d) a number divisible by 3 or divisible by 4? 2. Dario puts 44 marbles in a box in which 14 are red, 12 are blue, and 18 are yellow. If Dario picks one marble at random, what is the probability that he selects a red marble or a yellow marble? 3. Out of 5200 households surveyed, 2107 had a dog, 807 had a cat, and 303 had both a dog and a cat. What is the probability that a randomly selected household has a dog or a cat?

Solution

I see you've uploaded an image of a math activity involving probability and Venn diagrams. Let me extract and analyze the mathematical content to provide explanations and solutions. Give me a moment.The uploaded image contains probability problems involving the concepts of mutually exclusive events, combined probabilities, and event representation using Venn diagrams. Below is a breakdown and solution approach for each problem:

Activity 4: Taking Chances with Events A or B

1. Problem 1:

A bowl contains 15 chips numbered 1 to 15. If a chip is drawn randomly from the bowl, what is the probability that it is:

  • a multiple of 3
  • a number divisible by 5
  • divisible by both 3 and 5

Solution:

  • Multiples of 3: {3, 6, 9, 12, 15} → There are 5 such numbers.
    P(Multiple of 3)=515=13P(\text{Multiple of 3}) = \frac{5}{15} = \frac{1}{3}
  • Multiples of 5: {5, 10, 15} → There are 3 such numbers.
    P(Multiple of 5)=315=15P(\text{Multiple of 5}) = \frac{3}{15} = \frac{1}{5}
  • Multiples of both 3 and 5 (i.e., divisible by 15): {15} → Only 1 such number.
    P(Multiple of both 3 and 5)=115P(\text{Multiple of both 3 and 5}) = \frac{1}{15}
    Using the inclusion-exclusion principle: P(AB)=P(A)+P(B)P(AB)P(A \cup B) = P(A) + P(B) - P(A \cap B) P(Multiple of 3 or 5)=515+315115=715P(\text{Multiple of 3 or 5}) = \frac{5}{15} + \frac{3}{15} - \frac{1}{15} = \frac{7}{15}

2. Problem 2:

One puts 44 marbles in a box: 14 are red, 12 are blue, and 18 are yellow. If one picks one marble at random, what is the probability the marble is red or yellow?

Solution:
The total number of marbles is: 44=14+12+1844 = 14 + 12 + 18 The probability of picking a red marble: P(Red)=1444P(\text{Red}) = \frac{14}{44} The probability of picking a yellow marble: P(Yellow)=1844P(\text{Yellow}) = \frac{18}{44} Since these events are mutually exclusive, we can add the probabilities: P(Red or Yellow)=1444+1844=3244=811P(\text{Red or Yellow}) = \frac{14}{44} + \frac{18}{44} = \frac{32}{44} = \frac{8}{11}


3. Problem 3:

Out of 5200 households surveyed, 2107 had a dog, 807 had a cat, and 310 had both a dog and a cat. What is the probability that a randomly selected household has a dog or a cat?

Solution:
Using the inclusion-exclusion principle: P(Dog or Cat)=P(Dog)+P(Cat)P(Dog and Cat)P(\text{Dog or Cat}) = P(\text{Dog}) + P(\text{Cat}) - P(\text{Dog and Cat}) P(Dog)=21075200,P(Cat)=8075200,P(Dog and Cat)=3105200P(\text{Dog}) = \frac{2107}{5200}, \quad P(\text{Cat}) = \frac{807}{5200}, \quad P(\text{Dog and Cat}) = \frac{310}{5200} P(Dog or Cat)=21075200+80752003105200P(\text{Dog or Cat}) = \frac{2107}{5200} + \frac{807}{5200} - \frac{310}{5200} =26045200=5011000=0.501= \frac{2604}{5200} = \frac{501}{1000} = 0.501


Would you like detailed explanations of the Venn diagrams or a deeper analysis of mutual exclusivity in these events?

Five Related Questions

  1. How do you visualize probabilities using Venn diagrams effectively?
  2. What distinguishes mutually exclusive events from independent events?
  3. How does the inclusion-exclusion principle apply in real-life situations?
  4. How do probabilities change when sample spaces vary?
  5. What are practical applications of probabilities in surveys?

Tip:

When calculating "or" probabilities, always check whether the events overlap to apply the inclusion-exclusion principle properly.

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Math Problem Analysis

Mathematical Concepts

Probability
Set Theory
Mutually Exclusive Events
Inclusion-Exclusion Principle
Venn Diagrams

Formulas

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
P(A or B) = P(A) + P(B) if A and B are mutually exclusive

Theorems

Inclusion-Exclusion Principle
Basic Probability Theorems

Suitable Grade Level

Grades 8-10