We are tossing three coins together, so each coin has two possible outcomes: Head (H) or Tail (T). The total number of possible outcomes for three coins is $2^3 = 8$.

Let's first list all the possible outcomes of tossing three coins:

$\text{Outcomes} = \{ HHH, HHT, HTH, HTT, THH, THT, TTH, TTT \}$

(i) Probability of getting at least one head

The event "at least one head" means getting one or more heads. The only outcome where there are no heads is $TTT$.

So, the favorable outcomes are: $\{ HHH, HHT, HTH, HTT, THH, THT, TTH \}$

There are 7 favorable outcomes, so the probability is: $P(\text{at least one head}) = \frac{7}{8}$

(ii) Probability of getting at least two heads

The event "at least two heads" means getting two or three heads. The favorable outcomes for this event are: $\{ HHH, HHT, HTH, THH \}$

There are 4 favorable outcomes, so the probability is: \