To solve this probability problem, we need to determine the likelihood that Ralph will roll a "three" on a die both times.

Each die roll is independent, and the probability of rolling a "three" on a single roll of a standard six-sided die is $\frac{1}{6}$.

Since the rolls are independent, we multiply the probabilities of each event happening:

$\text{Probability of rolling a three twice} = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36}$

Therefore, the correct answer is:

C: $\frac{1}{36}$

Would you like more details, or do you have any questions?

Here are some related questions:

1. What is the probability of rolling the same number twice in a row with a die?
2. How would the probability change if Ralph rolled the die three times and wanted all threes?
3. What is the probability of rolling a number less than three on two consecutive rolls?
4. How does the probability change if using a different-sided die, like an 8-sided die?
5. What is the probability of rolling an even number twice in a row?

Tip: In probability, when dealing with independent events, always multiply the probabilities of each event occurring.