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To solve this probability problem, we need to determine the likelihood that Ralph will roll a "three" on a die both times.

Each die roll is independent, and the probability of rolling a "three" on a single roll of a standard six-sided die is \(\frac{1}{6}\).

Since the rolls are independent, we multiply the probabilities of each event happening:

\[
\text{Probability of rolling a three twice} = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36}
\]

Therefore, the correct answer is:

**C: \(\frac{1}{36}\)**

Would you like more details, or do you have any questions?

Here are some related questions:
1. What is the probability of rolling the same number twice in a row with a die?
2. How would the probability change if Ralph rolled the die three times and wanted all threes?
3. What is the probability of rolling a number less than three on two consecutive rolls?
4. How does the probability change if using a different-sided die, like an 8-sided die?
5. What is the probability of rolling an even number twice in a row?

**Tip:** In probability, when dealing with independent events, always multiply the probabilities of each event occurring.

Ralph rolls a single die two times in a row. What is the probability that he will roll a 'three' both times?

Learn how to calculate the probability of rolling a three on a six-sided die two times in a row. This problem introduces concepts of independent events in probability, suitable for Grades 6-8 students.

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