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The problem asks for the probability of obtaining a value "not less than 5" when rolling a single fair die.

A standard die has six faces, numbered 1 through 6. The numbers that are **not less than 5** are 5 and 6.

### Step-by-step solution:
1. **Favorable outcomes**: The possible outcomes where the roll is 5 or greater are {5, 6}.
   - So, there are 2 favorable outcomes.

2. **Total possible outcomes**: When rolling a die, there are 6 equally likely outcomes in total (1 through 6).

3. **Probability formula**: The probability \( P \) of an event is given by:
   \[
   P(\text{event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}
   \]

4. **Apply the values**:
   \[
   P(\text{not less than 5}) = \frac{2}{6} = \frac{1}{3}
   \]

So, the probability of obtaining a number not less than 5 is **1/3**.

Would you like more details, or do you have any questions?

Here are five related questions to think about:
1. What is the probability of rolling an even number on a fair die?
2. What is the probability of rolling a number less than 4?
3. If you roll two dice, what is the probability that the sum is 7?
4. How would the probability change if the die was not fair?
5. What is the probability of rolling a 5 twice in a row?

**Tip**: Simplify probabilities as much as possible to their lowest terms for clarity and correctness!

For the experiment of rolling a single fair die, find the probability of obtaining not less than 5.

Learn how to calculate the probability of rolling a number not less than 5 on a single fair die. The solution explains the key concepts of probability and combinatorics, making it suitable for students in Grades 5-7.

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