Math Problem Statement
A fair die is rolled 4 times. What is the probability of having number 2 and number 6 among the rolls?
Solution
We are tasked with finding the probability of rolling both a 2 and a 6 in four rolls of a fair die. Let’s break this down step-by-step:
Total Outcomes:
Since the die is rolled 4 times and each roll has 6 possible outcomes (numbers 1 through 6), the total number of outcomes is:
Favorable Outcomes:
To have both a 2 and a 6 among the rolls, let's consider the possible ways this can happen. We must choose two positions (out of the 4 rolls) to place the numbers 2 and 6, and then fill the remaining two positions with any of the other numbers (except for 2 and 6).
- Choosing positions for 2 and 6: We can choose 2 positions from the 4 rolls for the numbers 2 and 6. The number of ways to choose 2 positions from 4 is given by the combination:
- Arranging 2 and 6 in the chosen positions: There are 2 ways to arrange the numbers 2 and 6 in the selected positions (since we can put 2 in one of the positions and 6 in the other, or vice versa).
So, the total number of ways to place 2 and 6 is:
- Filling the remaining 2 positions: The remaining two positions can be filled with any number from 1, 3, 4, or 5 (since 2 and 6 are already used). Each of these two positions has 4 possible choices (numbers 1, 3, 4, or 5), so the total number of ways to fill these positions is:
Total favorable outcomes:
Thus, the total number of favorable outcomes is:
Probability:
Finally, the probability of having both a 2 and a 6 among the 4 rolls is:
So, the probability of having both a 2 and a 6 among the rolls is:
Would you like more details on this calculation or further explanation?
Here are some related questions for you to explore:
- What is the probability of rolling at least one 6 in four rolls?
- What is the probability of rolling all different numbers in four rolls?
- What is the probability of rolling exactly two 6's in four rolls?
- How many outcomes result in rolling no 2’s or 6’s in four rolls?
- What is the expected number of times a 2 is rolled in four rolls?
Tip: When calculating probabilities, start by identifying the total number of possible outcomes and then focus on finding favorable outcomes.
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Math Problem Analysis
Mathematical Concepts
Probability
Combinatorics
Formulas
Total outcomes = 6^4
Combination formula: C(n, k) = n! / (k!(n-k)!)
Probability formula: P = Number of favorable outcomes / Total outcomes
Theorems
Fundamental Counting Principle
Probability Theory
Suitable Grade Level
Grades 9-12