Math Problem Statement

in a class 70% are boys and 30% of girls 5% of boys 3% of girls are irregular to the classes what is the probability of the student selected at random in regular at the classes and what is the probability that the irregular student in a girls

Solution

Problem Analysis:

Let’s calculate the probabilities step by step:

  1. Class Composition:

    • 70% of the class are boys.
    • 30% of the class are girls.
  2. Irregular Attendance:

    • 5% of boys are irregular.
    • 3% of girls are irregular.
  3. Regular Attendance:

    • Regular boys: 100%5%=95%100\% - 5\% = 95\%.
    • Regular girls: 100%3%=97%100\% - 3\% = 97\%.

Probability Calculations

1. Probability of a randomly selected student being regular:

Let’s assume the total number of students in the class is NN (this cancels out in probabilities, so it’s not needed explicitly). We calculate the regular student proportion:

  • Regular boys:
    P(Regular Boys)=0.7×0.95=0.665P(\text{Regular Boys}) = 0.7 \times 0.95 = 0.665.

  • Regular girls:
    P(Regular Girls)=0.3×0.97=0.291P(\text{Regular Girls}) = 0.3 \times 0.97 = 0.291.

Total Probability of Regular Students: P(Regular)=P(Regular Boys)+P(Regular Girls)=0.665+0.291=0.956.P(\text{Regular}) = P(\text{Regular Boys}) + P(\text{Regular Girls}) = 0.665 + 0.291 = 0.956.

2. Probability that an irregular student is a girl:

Let’s calculate the total proportion of irregular students first:

  • Irregular boys:
    P(Irregular Boys)=0.7×0.05=0.035P(\text{Irregular Boys}) = 0.7 \times 0.05 = 0.035.

  • Irregular girls:
    P(Irregular Girls)=0.3×0.03=0.009P(\text{Irregular Girls}) = 0.3 \times 0.03 = 0.009.

Total Probability of Irregular Students: P(Irregular)=0.035+0.009=0.044.P(\text{Irregular}) = 0.035 + 0.009 = 0.044.

Now, the probability that an irregular student is a girl is: P(\text{Girl | Irregular}) = \frac{P(\text{Irregular Girls})}{P(\text{Irregular})} = \frac{0.009}{0.044} \approx 0.2045 \, (\text{20.45%}).


Final Answers:

  1. Probability of selecting a regular student: P(\text{Regular}) = 0.956 \, (\text{95.6%}).

  2. Probability that an irregular student is a girl: P(\text{Girl | Irregular}) \approx 0.2045 \, (\text{20.45%}).


Would you like a step-by-step breakdown or clarification on any part of the calculation?


Related Questions:

  1. How would the probabilities change if the percentage of boys and girls were equal?
  2. What is the probability that a randomly selected boy is regular?
  3. If there are 100 students, how many boys and girls are regular?
  4. How does increasing the irregularity percentage for girls affect P(Regular)P(\text{Regular})?
  5. How can this problem be modeled using a tree diagram?

Tip:

Always double-check probabilities sum to 1 when solving problems involving complementary events like regularity and irregularity.

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Math Problem Analysis

Mathematical Concepts

Probability
Conditional Probability
Percentage Calculations

Formulas

P(Regular) = P(Regular Boys) + P(Regular Girls)
P(Regular Boys) = (Percentage of Boys) × (Percentage of Regular Boys)
P(Regular Girls) = (Percentage of Girls) × (Percentage of Regular Girls)
P(Girl | Irregular) = P(Irregular Girls) / P(Irregular)

Theorems

Law of Total Probability
Bayes' Theorem (applied for conditional probability)

Suitable Grade Level

Grades 9-12