To solve this, we need to find the conditional probability that a student has an A, given that the student is female. This can be represented as:

$P(\text{Has an A} \mid \text{Female}) = \frac{P(\text{Has an A and Female})}{P(\text{Female})}$

Step 1: Calculate $P(\text{Has an A and Female})$

This is the probability of selecting a female student who has an A. From the table, we know there are 5 female students who have an A.

Step 2: Calculate $P(\text{Female})$

This is the probability of selecting a female student. The total number of female students is: $5 (\text{Has an A}) + 10 (\text{Does not have an A}) = 15 \text{ female students}.$

Step 3: Conditional Probability Formula

Now we can substitute into the conditional probability formula:

$P(\text{Has an A} \mid \text{Female}) = \frac{5}{15} = \frac{1}{3}$

So, the probability that a student has an A given that the student is female is:

$\boxed{\frac{1}{3}}$

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Would you like more details or have any follow-up questions?

Here are some related questions you might find useful:

1. How would the probability change if we were looking for a male student instead?
2. What is the total probability of a student having an A in the class?
3. How do you calculate the probability of an event with multiple conditions (e.g., a student is male and has an A)?
4. What is the interpretation of conditional probability in this context?
5. How would the probability change if more students were added to the class?

Tip: Always check if the events are independent before applying simple probability rules. Conditional probabilities require knowing the context or event we're conditioning on.