To express the degree of likelihood as a probability value between 0 and 1, we use the formula:

$\text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$

In this case, the favorable outcome is that the last digit is zero (1 chance), and the total number of possible outcomes is 10 (since the last digit can be any digit from 0 to 9).

Thus, the probability is:

$P(\text{last digit is 0}) = \frac{1}{10} = 0.1$

So, the probability that the last digit is zero is 0.1.

Would you like more details or have any questions about this?

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Here are 5 related questions:

1. What is the probability that the last digit is not zero?
2. How would the probability change if there were 20 possible outcomes?
3. Can you convert this probability to a percentage?
4. What is the complement of this probability?
5. How would you calculate the probability of randomly generating an odd last digit?

Tip: Probabilities always range between 0 and 1, where 0 means impossible and 1 means certain.