Math Problem Statement

A number and a letter are taken out randomly from set A = {2, 3, 6, 7} and set B = {R, E, D}. Find the probability of getting (a) a prime number and a vowel, (b) an odd number and a consonant.

Solution

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Question:

There are two sets:

  • Set A={2,3,6,7}A = \{2, 3, 6, 7\} contains numbers.
  • Set B={R,E,D}B = \{R, E, D\} contains letters.

The task involves randomly selecting one number from set AA and one letter from set BB.

  1. (a) Senaraikan ruang sampel (List the sample space):

    The sample space consists of all possible combinations of one number from set AA and one letter from set BB.

    Sample space SS: S={(2,R),(2,E),(2,D),(3,R),(3,E),(3,D),(6,R),(6,E),(6,D),(7,R),(7,E),(7,D)}S = \{(2, R), (2, E), (2, D), (3, R), (3, E), (3, D), (6, R), (6, E), (6, D), (7, R), (7, E), (7, D)\} There are 12 possible outcomes.

  2. (b) Cari kebarangkalian bagi mendapatkan (Find the probability of getting):

    1. Satu nombor perdana dan satu vokal (a prime number and a vowel):

      • Prime numbers from set A={2,3,6,7}A = \{2, 3, 6, 7\}: The prime numbers are 2,3,72, 3, 7.
      • Vowels from set B={R,E,D}B = \{R, E, D\}: The vowel is EE.

      The favorable outcomes are combinations of prime numbers with the vowel EE: {(2,E),(3,E),(7,E)}\{(2, E), (3, E), (7, E)\} There are 3 favorable outcomes.

      Probability P(prime and vowel)=Number of favorable outcomesTotal outcomes=312=14P(\text{prime and vowel}) = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{3}{12} = \frac{1}{4}.

    2. Satu nombor ganjil dan satu konsonan (an odd number and a consonant):

      • Odd numbers from set A={2,3,6,7}A = \{2, 3, 6, 7\}: The odd numbers are 3,73, 7.
      • Consonants from set B={R,E,D}B = \{R, E, D\}: The consonants are R,DR, D.

      The favorable outcomes are combinations of odd numbers with consonants: {(3,R),(3,D),(7,R),(7,D)}\{(3, R), (3, D), (7, R), (7, D)\} There are 4 favorable outcomes.

      Probability P(odd and consonant)=412=13P(\text{odd and consonant}) = \frac{4}{12} = \frac{1}{3}.

Answer Summary:

  • (a) The sample space is {(2,R),(2,E),(2,D),(3,R),(3,E),(3,D),(6,R),(6,E),(6,D),(7,R),(7,E),(7,D)}\{(2, R), (2, E), (2, D), (3, R), (3, E), (3, D), (6, R), (6, E), (6, D), (7, R), (7, E), (7, D)\}.
  • (b)
    1. Probability of getting a prime number and a vowel: 14\frac{1}{4}.
    2. Probability of getting an odd number and a consonant: 13\frac{1}{3}.

Would you like more details or have any other questions?

Here are 5 related questions:

  1. What is the probability of getting a number greater than 5 and a letter DD?
  2. How would the probabilities change if another vowel was added to set BB?
  3. What if the number set AA was expanded to include more even numbers?
  4. What is the probability of getting an even number and a consonant?
  5. How many possible outcomes would there be if set BB had 5 letters instead of 3?

Tip: When calculating probabilities, always ensure to correctly list the total sample space and count favorable outcomes based on specific conditions.

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Math Problem Analysis

Mathematical Concepts

Probability
Sample Space

Formulas

Probability = (Number of favorable outcomes) / (Total outcomes)

Theorems

Basic Probability Theory

Suitable Grade Level

Grades 6-8