Math Problem Statement

Continue problem 1: A survey was conducted from 500 people to determine the probability of a person owning a car given that the person owns a pet. The results showed that 100 out of 300 pet owners also own a car. What is the probability that a randomly selected person owns a pet and a car?

Solution

To find the probability that a randomly selected person owns both a pet and a car, we use the information provided in the problem.

Solution

  1. Total number of people surveyed: N=500N = 500.

  2. Number of pet owners who also own a car: 100.

  3. To determine the probability that a randomly selected person owns both a pet and a car, we calculate: P(owns a pet and a car)=Number of people who own both a pet and a carTotal number of people surveyedP(\text{owns a pet and a car}) = \frac{\text{Number of people who own both a pet and a car}}{\text{Total number of people surveyed}}

  4. Substituting the values: P(owns a pet and a car)=100500=0.2P(\text{owns a pet and a car}) = \frac{100}{500} = 0.2

Answer

The probability that a randomly selected person owns both a pet and a car is 0.2, or 20%.

Would you like further details or have additional questions?


Here are some related questions to deepen your understanding:

  1. What is the probability that a randomly selected person owns a car, regardless of pet ownership?
  2. What is the probability that a randomly selected person owns only a pet but not a car?
  3. If a person is known not to own a car, what is the probability that they own a pet?
  4. How would the probability change if the total number of pet owners was different?
  5. What is the probability that a randomly selected person owns neither a pet nor a car?

Tip: When calculating joint probabilities, always ensure you know the total number of events in your population to determine accuracy.

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Math Problem Analysis

Mathematical Concepts

Probability
Statistics

Formulas

P(A and B) = Number of A and B / Total number of outcomes

Theorems

Joint probability theorem

Suitable Grade Level

Grades 9-12