Let's solve each of these questions one by one.

1. What is the probability of 3 heads?

   For 3 heads, we need to get a head on each flip. Each flip is independent, so:

   $P(\text{3 heads}) = \left(\frac{1}{2}\right)^3 = \frac{1}{8}$

2. What is the probability of 2 heads and 1 tail in any order?

   There are three ways to get 2 heads and 1 tail: HHT, HTH, and THH. Each sequence has a probability of $\frac{1}{8}$, so:

   $P(\text{2 heads and 1 tail}) = 3 \times \frac{1}{8} = \frac{3}{8}$

3. What is the probability of 1 head and 2 tails in any order?

   Similarly, there are three ways to get 1 head and 2 tails: HTT, THT, and TTH. Each sequence also has a probability of $\frac{1}{8}$, so:

   $P(\text{1 head and 2 tails}) = 3 \times \frac{1}{8} = \frac{3}{8}$

4. What is the probability of 3 tails?

   For 3 tails, we need a tail on each flip. Thus:

   $P(\text{3 tails}) = \left(\frac{1}{2}\right)^3 = \frac{1}{8}$

Summary of Answers:

1. Probability of 3 heads: 1/8
2. Probability of 2 heads and 1 tail: 3/8
3. Probability of 1 head and 2 tails: 3/8
4. Probability of 3 tails: 1/8

Would you like further details on any of these steps?

Related Questions:

1. What is the probability of getting at least one head in 3 flips?
2. How would the probabilities change if the coin was biased with a 0.6 chance of landing heads?
3. If the coin was flipped 4 times, what is the probability of getting exactly 2 heads?
4. What is the probability of getting a specific sequence, like HTT, in 3 flips?
5. What is the probability of getting an equal number of heads and tails in 4 flips?

Tip:

In probability, when dealing with multiple independent events, multiplying the individual probabilities is essential for calculating the probability of a specific sequence.