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To find the probability of selecting a DVR that is *not defective*, we need to follow these steps:

1. **Total DVRs**: 200
2. **Defective DVRs**: 26

To get the number of *non-defective* DVRs, subtract the defective ones from the total number:

\[
\text{Non-defective DVRs} = 200 - 26 = 174
\]

The probability of randomly selecting a non-defective DVR is the ratio of non-defective DVRs to the total number of DVRs:

\[
P(\text{not defective}) = \frac{174}{200} = 0.87
\]

So, the probability of selecting a non-defective DVR is **0.87**.

Would you like further explanation or have any additional questions?

Here are some related questions to explore:
1. How would the probability change if there were 30 defective DVRs instead of 26?
2. What is the probability of selecting a defective DVR?
3. How would you express this probability as a percentage?
4. If 50 more DVRs are added, with 10 being defective, how does that affect the probability?
5. How can you calculate the odds in favor of selecting a non-defective DVR?

**Tip**: Always remember that the probability is simply a ratio between the favorable outcomes and the total possible outcomes.

Twenty-six of the 200 digital video recorders (DVRs) in an inventory are known to be defective. What is the probability you randomly select a DVR that is not defective?

Find the probability of randomly selecting a non-defective DVR from an inventory where 26 out of 200 DVRs are defective. Learn how to calculate probabilities using simple ratios. This problem is suitable for students in Grades 6-8.

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