To find the probability of selecting a DVR that is not defective, we need to follow these steps:

1. Total DVRs: 200
2. Defective DVRs: 26

To get the number of non-defective DVRs, subtract the defective ones from the total number:

$\text{Non-defective DVRs} = 200 - 26 = 174$

The probability of randomly selecting a non-defective DVR is the ratio of non-defective DVRs to the total number of DVRs:

$P(\text{not defective}) = \frac{174}{200} = 0.87$

So, the probability of selecting a non-defective DVR is 0.87.

Would you like further explanation or have any additional questions?

Here are some related questions to explore:

1. How would the probability change if there were 30 defective DVRs instead of 26?
2. What is the probability of selecting a defective DVR?
3. How would you express this probability as a percentage?
4. If 50 more DVRs are added, with 10 being defective, how does that affect the probability?
5. How can you calculate the odds in favor of selecting a non-defective DVR?

Tip: Always remember that the probability is simply a ratio between the favorable outcomes and the total possible outcomes.