Math Problem Statement

Three events A, B, and C satisfy P(A^c) = 0.3, P(B) = 0.5, P(C) = 0.2, P(B ∪ C) = 0.6, P(A ∩ B) = 0.4. (a) What is P(B ∩ C)? (b) What is P(B^c | A)? (c) Are A and B independent?

Solution

Let’s analyze and solve each part of the problem step by step.

Given Information

We have three events AA, BB, and CC with the following probabilities:

  • P(Ac)=0.3P(A^c) = 0.3
  • P(B)=0.5P(B) = 0.5
  • P(C)=0.2P(C) = 0.2
  • P(BC)=0.6P(B \cup C) = 0.6
  • P(AB)=0.4P(A \cap B) = 0.4

We can derive P(A)P(A) using the complement rule: P(A)=1P(Ac)=10.3=0.7P(A) = 1 - P(A^c) = 1 - 0.3 = 0.7

Part (a): Find P(BC)P(B \cap C)

Using the formula for the union of two events: P(BC)=P(B)+P(C)P(BC)P(B \cup C) = P(B) + P(C) - P(B \cap C) Substituting the known values: [ 0.6

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Math Problem Analysis

Mathematical Concepts

Probability
Complement Rule
Conditional Probability
Independence of Events

Formulas

Complement Rule: P(A) = 1 - P(A^c)
Union of Events: P(B ∪ C) = P(B) + P(C) - P(B ∩ C)
Conditional Probability: P(B^c | A) = P(A ∩ B^c) / P(A)
Independence: P(A ∩ B) = P(A) * P(B)

Theorems

Basic Probability Theorems

Suitable Grade Level

Grades 11-12