Math Problem Statement

If A and B are independent events with P(A)=0.4 and P(B)=0.9, find P(A AND B).

Solution

If AA and BB are independent events, the probability of both AA and BB happening together, denoted as P(A AND B)P(A \text{ AND } B), is given by the product of their individual probabilities:

P(A AND B)=P(A)×P(B)P(A \text{ AND } B) = P(A) \times P(B)

Given that:

P(A)=0.4andP(B)=0.9,P(A) = 0.4 \quad \text{and} \quad P(B) = 0.9,

we can calculate:

P(A AND B)=0.4×0.9=0.36.P(A \text{ AND } B) = 0.4 \times 0.9 = 0.36.

Thus, P(A AND B)=0.36P(A \text{ AND } B) = 0.36.

Would you like more details or have any further questions?

Here are 5 related questions:

  1. What is the probability of AA or BB happening, i.e., P(A OR B)P(A \text{ OR } B)?
  2. How do you calculate the probability of AA given that BB has occurred?
  3. If P(A)=0.4P(A) = 0.4 and P(B)=0.9P(B) = 0.9, what is the probability of neither AA nor BB happening?
  4. What would happen to the probability if AA and BB were mutually exclusive instead of independent?
  5. Can two events be independent and mutually exclusive at the same time? Why or why not?

Tip: Independence means that knowing the outcome of one event does not affect the probability of the other event occurring.

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Math Problem Analysis

Mathematical Concepts

Probability
Independent Events

Formulas

P(A AND B) = P(A) × P(B)

Theorems

Multiplication Rule for Independent Events

Suitable Grade Level

Grades 9-11