Math Problem Statement

Events A and B are independent events. Find the indicated Probability: P(A) = 0.6, P(B) = 0.3, P(A and B) = ?

Solution

The problem states that events AA and BB are independent, with the following probabilities provided:

P(A)=0.6,P(B)=0.3P(A) = 0.6, \quad P(B) = 0.3

For independent events, the probability of both AA and BB occurring (i.e., P(A and B)P(A \text{ and } B)) is found by multiplying their individual probabilities:

P(A and B)=P(A)×P(B)P(A \text{ and } B) = P(A) \times P(B)

Substituting the given values:

P(A and B)=0.6×0.3=0.18P(A \text{ and } B) = 0.6 \times 0.3 = 0.18

So, the probability that both events occur is:

P(A and B)=0.18P(A \text{ and } B) = 0.18

Would you like more details or have any further questions?

Here are 5 related questions:

  1. What is the probability of A or BA \text{ or } B occurring for independent events?
  2. How does independence affect the calculation of conditional probabilities?
  3. What would change if AA and BB were not independent?
  4. Can the probability of two mutually exclusive events be calculated similarly?
  5. How is the probability of the complement of A and BA \text{ and } B determined?

Tip: When dealing with independent events, always remember to multiply their probabilities to find the combined outcome.

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Math Problem Analysis

Mathematical Concepts

Probability
Independent Events

Formulas

P(A and B) = P(A) * P(B)

Theorems

Multiplication Rule for Independent Events

Suitable Grade Level

Grades 9-12