We are asked to find the probability that the pedestrian was not intoxicated but the driver was intoxicated.

From the table:

• The number of cases where the driver was intoxicated and the pedestrian was not intoxicated is 85.

• The total number of pedestrian deaths is $52 + 85 + 231 + 618 = 986$.

The probability is the ratio of favorable cases (driver intoxicated, pedestrian not intoxicated) to the total cases:

$P(\text{Driver Intoxicated, Pedestrian Not Intoxicated}) = \frac{85}{986}$

Let's calculate this ratio.

$\frac{85}{986} \approx 0.0862$

So, the probability is approximately 0.0862.

Would you like further details on this or have any other questions?

Here are some related questions:

1. What is the probability that both the driver and pedestrian were intoxicated?
2. What is the probability that neither the driver nor the pedestrian was intoxicated?
3. How would the probability change if there were more intoxicated drivers?
4. What is the total probability of pedestrian intoxication?
5. How do probabilities change with increasing or decreasing sample sizes?

Tip: Always ensure the total number of outcomes matches the data provided to avoid calculation errors.