The table summarizes results from 978 pedestrian deaths that were caused by automobile accidents.

Pedestrian Deaths
Driver
Intoxicated?	Pedestrian Intoxicated?
Yes	No
Yes	44	73
No	221	640
If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was not intoxicated or the driver was not intoxicated. Please enter a decimal to 4 decimal places.

Probability = 
0.9550


To solve this, we need to find the probability that either the pedestrian was not intoxicated or the driver was not intoxicated, or both. This can be calculated using the formula for the union of two events:

\[
P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B)
\]

Where:
- \( A \) is the event that the pedestrian was not intoxicated.
- \( B \) is the event that the driver was not intoxicated.

### Step 1: Total number of pedestrian deaths
The total number of pedestrian deaths is given as 978.

### Step 2: Probabilities for each event
1. **Pedestrian not intoxicated**: This includes both cases where the driver was intoxicated and where the driver was not intoxicated, with the pedestrian being sober.
   \[
   P(A) = \frac{73 + 640}{978} = \frac{713}{978}
   \]

2. **Driver not intoxicated**: This includes both cases where the pedestrian was intoxicated and where the pedestrian was not intoxicated, with the driver being sober.
   \[
   P(B) = \frac{221 + 640}{978} = \frac{861}{978}
   \]

3. **Both pedestrian and driver not intoxicated**: This is the case where both the pedestrian and the driver were sober, which corresponds to 640 cases.
   \[
   P(A \text{ and } B) = \frac{640}{978}
   \]

### Step 3: Calculate the union probability
Now, substitute these values into the union formula:

\[
P(A \text{ or } B) = \frac{713}{978} + \frac{861}{978} - \frac{640}{978}
\]

\[
P(A \text{ or } B) = \frac{713 + 861 - 640}{978} = \frac{934}{978}
\]

### Step 4: Simplify and convert to decimal
\[
P(A \text{ or } B) = \frac{934}{978} \approx 0.9550
\]

Thus, the probability that the pedestrian was not intoxicated or the driver was not intoxicated is \( \boxed{0.9550} \).

Would you like further clarification or more details?

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Here are 5 related questions you might explore:
1. What is the probability that both the pedestrian and the driver were intoxicated?
2. What is the probability that only the pedestrian was intoxicated?
3. What is the probability that only the driver was intoxicated?
4. If another sample of 2000 pedestrian deaths were taken, how would this probability change?
5. How would the probability change if 50 more intoxicated pedestrians were added to the data?

**Tip:** When dealing with probabilities of unions, always account for overlaps to avoid double-counting.

The table summarizes results from 978 pedestrian deaths that were caused by automobile accidents.

Pedestrian Deaths
Driver
Intoxicated? Pedestrian Intoxicated?
Yes No
Yes 44 73
No 221 640
If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was not intoxicated or the driver was not intoxicated. Please enter a decimal to 4 decimal places.

Probability = 0.9550

Find the probability that either a pedestrian or driver was not intoxicated in a sample of 978 pedestrian deaths caused by automobile accidents. Using the union of events probability formula, the solution covers key concepts in probability theory. Perfect for students in Grades 9-12.

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