To find the probability that both selected pedestrian deaths involved intoxicated pedestrians, we'll follow these steps:

1. Calculate the Total Number of Pedestrian Deaths: Add up all the values in the table to find the total number of pedestrian deaths.

   $\text{Total} = 57 + 85 + 269 + 577 = 988$

2. Calculate the Total Number of Pedestrian Deaths Where Pedestrians Were Intoxicated: Add the numbers in the rows where the pedestrian was intoxicated.

   $\text{Total Intoxicated Pedestrians} = 57 + 85 = 142$

3. Calculate the Probability of Selecting Two Intoxicated Pedestrians: The probability of selecting one intoxicated pedestrian is the ratio of intoxicated pedestrians to the total number of pedestrian deaths. After selecting the first intoxicated pedestrian, the probability of selecting a second one from the remaining pedestrians is the ratio of the remaining intoxicated pedestrians to the remaining total number of pedestrians.

   $P(\text{Both Intoxicated}) = \frac{142}{988} \times \frac{141}{987}$

4. Calculate the Exact Probability:

   $P(\text{Both Intoxicated}) = \frac{142 \times 141}{988 \times 987}$

   $P(\text{Both Intoxicated}) \approx \frac{20022}{975156} \approx 0.02054$

5. Final Answer: The probability that both selected pedestrian deaths involved intoxicated pedestrians is approximately 0.0205 when rounded to four decimal places.

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Do you want more details or have any questions?

Here are 5 related questions to consider:

1. What is the probability of selecting two non-intoxicated pedestrians?
2. How would the probability change if the number of pedestrian deaths increased?
3. What is the probability of selecting one intoxicated and one non-intoxicated pedestrian?
4. How can we apply these probabilities to predict future pedestrian deaths?
5. What is the significance of considering driver intoxication in this context?

Tip: Always double-check your calculations by breaking down each step to ensure accuracy, especially in probability problems involving multiple selections.