To write 54 as a product of prime factors, let's first find the prime factorization of 54:

1. Divide 54 by the smallest prime number (2): $54 \div 2 = 27$ So, 54 = 2 × 27.

2. Now, divide 27 by the smallest prime number that divides it (3): $27 \div 3 = 9$ So, 27 = 3 × 9, and thus 54 = 2 × 3 × 9.

3. Continue factoring 9: $9 = 3 \times 3$ So, 54 = 2 × 3 × 3 × 3.

Now, write the prime factors using exponents where applicable: $54 = 2 \times 3^3$

In your homework interface, you can input $2 \times 3^3$ as the answer.

Would you like more details or have any questions?

Here are 5 related questions for practice:

1. What is the prime factorization of 72?
2. How do you find the prime factors of 100?
3. What is the prime factorization of 81?
4. What is the prime factorization of 45?
5. Can you factor 108 into prime factors?

Tip: When factoring numbers, always start with the smallest prime number (2) and proceed to the next primes (3, 5, 7, etc.) until you completely factor the number.