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The image shows a question asking for the prime factorization of 231. The choices are:

1. \(3 \times 7 \times 11\)
2. \(3^2 \times 7 \times 11\)
3. \(3 \times 2^2 \times 7\)
4. \(3 \times 7^2 \times 11\)

To solve this, let's determine the prime factorization of 231:

1. 231 is divisible by 3, because the sum of its digits \(2+3+1=6\) is divisible by 3. Dividing, \(231 \div 3 = 77\).
2. 77 is divisible by 7 (since \(77 \div 7 = 11\)).
3. The quotient 11 is a prime number.

So, the prime factorization of 231 is \(3 \times 7 \times 11\), which corresponds to the first option.

Do you need more details or have any further questions about prime factorization? Here are some related questions:

1. How do you check if a number is prime?
2. What is the prime factorization of 330?
3. Why is the knowledge of prime numbers important in mathematics?
4. How can the prime factorization be used in real-life applications?
5. What are some methods to find prime numbers within a specific range?

**Tip:** To check for divisibility by 3, sum the digits of the number. If the sum is divisible by 3, then the original number is also divisible by 3.

Discover how to find the prime factorization of 231 through simple steps using divisibility rules. This problem highlights key number theory concepts and is suitable for students in Grades 6-8.

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