Math Problem Statement

Let A be a set and let B be the set of all the subsets of A. (a) Is it possible for B to contain exactly one set of cardinality 7? If the answer is positive, what can you say about A? Justify your answers. (b) Is it possible for B to contain exactly two sets of cardinality 7? If the answer is positive, what can you say about A? Justify your answers

Solution

Let’s analyze the problem step by step.

(a) Is it possible for BB to contain exactly one set of cardinality 7?

Step 1: Understanding the set BB

  • AA is a set, and BB is the power set of AA. This means that BB contains all subsets of AA.
  • The number of subsets of AA is 2A2^{|A|}, where A|A| is the cardinality of AA (i.e., the number of elements in AA).
  • Among these subsets, we are particularly interested in those subsets of cardinality 7.

Step 2: Analyzing the problem

For BB to contain exactly one subset of cardinality 7, the original set AA must have at least 7 elements. The number of subsets of a set AA of cardinality nn, that have cardinality 7 is given by the binomial coefficient (n7)\binom{n}{7}.

So we require:

(n7)=1\binom{n}{7} = 1

This condition implies that nn must be exactly 7 because:

(n7)=1if and only ifn=7\binom{n}{7} = 1 \quad \text{if and only if} \quad n = 7

Conclusion for (a)

  • Yes, it is possible for BB to contain exactly one set of cardinality 7 if and only if AA has exactly 7 elements. In this case, the only subset of cardinality 7 is AA itself.

(b) Is it possible for BB to contain exactly two sets of cardinality 7?

Step 1: Reconsidering the number of subsets of cardinality 7

For BB to contain exactly two subsets of cardinality 7, we need:

(n7)=2\binom{n}{7} = 2

However, the binomial coefficient (n7)\binom{n}{7} only takes integer values and increases as nn increases. The smallest values for (n7)\binom{n}{7} as nn increases are as follows:

  • (77)=1\binom{7}{7} = 1
  • (87)=8\binom{8}{7} = 8
  • (97)=36\binom{9}{7} = 36

There is no nn such that (n7)=2\binom{n}{7} = 2. Therefore, it is impossible for BB to contain exactly two subsets of cardinality 7.

Conclusion for (b)

  • No, it is not possible for BB to contain exactly two sets of cardinality 7.

Summary:

  • (a) Yes, BB can contain exactly one set of cardinality 7 if and only if AA has exactly 7 elements.
  • (b) No, it is not possible for BB to contain exactly two sets of cardinality 7.

Would you like more details on any part of the reasoning?

Here are some related questions for deeper understanding:

  1. What is the power set of a set, and how is it calculated?
  2. How does the binomial coefficient (nk)\binom{n}{k} relate to subsets of a given cardinality?
  3. Can we calculate the exact number of subsets of a given size for any set?
  4. How would the situation change if we asked about subsets of a different cardinality, say 5?
  5. What is the total number of subsets in a set of cardinality nn?

Tip: Understanding how binomial coefficients work is essential when analyzing problems involving subsets. These coefficients give us the number of ways to choose subsets of a specific size from a set.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Set Theory
Combinatorics
Power Set

Formulas

Number of subsets of a set A = 2^|A|
Binomial coefficient: C(n, k) = n! / (k!(n-k)!)

Theorems

Binomial Coefficient Theorem
Properties of Power Sets

Suitable Grade Level

Undergraduate