To calculate the power dissipated in the cable, we can use the following formula based on Joule's law of heating:

$P = I^2 \cdot R$

Where:

• $P$ is the power dissipated (in watts, W),
• $I$ is the current (in amperes, A),
• $R$ is the total resistance of the cable (in ohms, $\Omega$).

First, we need to calculate the total resistance of the cable:

$R = \text{Resistance per metre} \times \text{Length of the cable}$ $R = 0.003 \, \Omega/\text{m} \times 80 \, \text{m} = 0.24 \, \Omega$

Now, use the formula for power dissipation:

$P = 10^2 \times 0.24 = 100 \times 0.24 = 24 \, \text{W}$

Thus, the power dissipated in the cable is 24 watts.

Do you want more details or have any questions about this?

Here are 5 related questions for further exploration:

1. How does the power dissipation change if the current increases to 15 A?
2. What would be the total resistance for a cable that is 100 meters long?
3. How much energy would be dissipated over 1 hour of continuous current flow?
4. How does reducing the cable length affect the power dissipated?
5. What is the effect of using a cable with higher resistance per meter?

Tip: Power dissipation increases with the square of the current, meaning a small increase in current results in a significant increase in power loss.