To solve this, let the three-digit number be represented by $abc$, where $a$, $b$, and $c$ are its digits. We know that the sum of these digits is:

$a + b + c = 15$

We are asked to find which of the following is a possible product of these three digits:

$a \times b \times c$

We need to explore different combinations of digits whose sum is 15 and then calculate their product.

Possible combinations:

• $a = 9, b = 5, c = 1$:
  Sum: $9 + 5 + 1 = 15$,
  Product: $9 \times 5 \times 1 = 45$.

• $a = 8, b = 6, c = 1$:
  Sum: $8 + 6 + 1 = 15$,
  Product: $8 \times 6 \times 1 = 48$.

• $a = 7, b = 5, c = 3$:
  Sum: $7 + 5 + 3 = 15$,
  Product: $7 \times 5 \times 3 = 105$.

• $a = 6, b = 6, c = 3$:
  Sum: $6 + 6 + 3 = 15$,
  Product: $6 \times 6 \times 3 = 108$.

Conclusion:

The possible products are 45, 48, 105, and 108. Depending on the given options, these products will help identify which one is correct.

Would you like more details or have further questions?

Related questions:

1. What is the maximum possible product of the digits given their sum is 15?
2. How many different combinations of digits can sum to 15?
3. What is the minimum product of the digits if their sum is 15?
4. Can a combination of three identical digits sum to 15? What would their product be?
5. How does changing the sum of the digits affect the possible products?

Tip:

When solving digit problems, it's helpful to consider both the sum and product properties of common digit combinations to quickly identify valid numbers.