Math Problem Statement

From expressions above, form the acceleration vector a = arˆ r+aθ ˆ θ. Say something interesting about it.

Solution

To express the acceleration of point AA in vector form, we will use polar coordinates with two components: radial and tangential.

1. Radial acceleration component ara_r:

Radial acceleration is directed towards the center of the circular path of motion. Since point AA is moving along a circle of radius R+rR + r, the radial component of the acceleration is given by:

ar=(R+r)Ω2Ra_r = \frac{(R + r) \Omega^2}{R}

This is the centripetal acceleration, pointing towards the center OO of the ring.

2. Tangential acceleration component aθa_\theta:

As mentioned earlier, since the angular velocity Ω\Omega is constant (i.e., there is no angular acceleration), there is no tangential acceleration:

aθ=0a_\theta = 0

3. Acceleration vector:

The total acceleration a\mathbf{a} of point AA can therefore be written in vector form as:

a=arr^+aθθ^\mathbf{a} = a_r \hat{r} + a_\theta \hat{\theta}

Substituting the values of ara_r and aθa_\theta, we get:

a=(R+r)Ω2Rr^+0θ^\mathbf{a} = \frac{(R + r) \Omega^2}{R} \hat{r} + 0 \hat{\theta}

This simplifies to:

[ \mathbf{a} = \frac{(R + r

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Math Problem Analysis

Mathematical Concepts

Polar Coordinates
Vector Analysis
Centripetal Acceleration

Formulas

a_r = (R + r) Ω^2 / R
a_θ = 0
a = a_r r̂ + a_θ θ̂

Theorems

Centripetal acceleration theorem

Suitable Grade Level

Grades 11-12