The point-slope form of a line's equation is given by:

$y - y_1 = m(x - x_1)$

Where:

• $(x_1, y_1)$ is a point on the line,
• $m$ is the slope of the line.

Given:

• $(x_1, y_1) = (16, -1)$,
• $m = 33$,

Substitute the values into the formula:

$y - (-1) = 33(x - 16)$

Simplifying:

$y + 1 = 33(x - 16)$

Now distribute the 33 on the right side:

$y + 1 = 33x - 528$

Finally, subtract 1 from both sides to solve for $y$:

$y = 33x - 529$

So, the equation of the line is:

$y = 33x - 529$

Do you want more details or have any questions?

Here are some related questions:

1. How can we convert this equation into slope-intercept form?
2. What is the general form of the equation of a line?
3. How would you graph this line using the point and slope?
4. Can you find the x-intercept of this line?
5. How does point-slope form compare to the standard form?

Tip: The point-slope form is useful for writing the equation of a line quickly when you know a point and the slope.