Use point-slope form to write the equation of a line that passes through the point left parenthesis, 16, comma, minus, 1, right parenthesis(16,−1) with slope 33.

The point-slope form of a line is given by:

\[
y - y_1 = m(x - x_1)
\]

where \((x_1, y_1)\) is a point on the line, and \(m\) is the slope.

Given:
- Point \((x_1, y_1) = (16, -1)\)
- Slope \(m = 33\)

Substituting these values into the point-slope form equation:

\[
y - (-1) = 33(x - 16)
\]

Simplifying:

\[
y + 1 = 33(x - 16)
\]

This is the equation of the line in point-slope form.

Do you want more details or have any questions?

Here are 5 related questions:
1. How do you convert point-slope form to slope-intercept form?
2. What is the general form of a linear equation?
3. How would you find the x-intercept and y-intercept of this line?
4. What if the slope were negative—how would the line's equation change?
5. How would you find the distance between two points on the line?

**Tip**: Remember that the point-slope form is particularly useful when you know the slope and one point on the line!

Use point-slope form to write the equation of a line that passes through the point (16,−1) with slope 33.

Learn how to write the equation of a line in point-slope form that passes through the point (16,−1) with a slope of 33. This problem covers essential algebraic concepts, including the point-slope formula, and is suitable for students in Grades 8-10.

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