Here are the correct plotting points for the function:

$h(x) = 0.1(x + 2)^2(x - 3)^3$

We'll use integer values for $x$ and compute the corresponding $h(x)$ values:

Step 1: Calculate $h(x)$ for integer values of $x$

1. For $x = -4$: $h(-4) = 0.1(-4 + 2)^2(-4 - 3)^3 = 0.1(-2)^2(-7)^3 = 0.1(4)(-343) = -137.2$ So, the point is $(-4, -137.2)$.

2. For $x = -3$: $h(-3) = 0.1(-3 + 2)^2(-3 - 3)^3 = 0.1(-1)^2(-6)^3 = 0.1(1)(-216) = -21.6$ So, the point is $(-3, -21.6)$.

3. For $x = -2$: $h(-2) = 0.1(-2 + 2)^2(-2 - 3)^3 = 0.1(0)^2(-5)^3 = 0$ So, the point is $(-2, 0)$.

4. For $x = 0$: $h(0) = 0.1(0 + 2)^2(0 - 3)^3 = 0.1(2)^2(-3)^3 = 0.1(4)(-27) = -10.8$ So, the point is $(0, -10.8)$.

5. For $x = 1$: $h(1) = 0.1(1 + 2)^2(1 - 3)^3 = 0.1(3)^2(-2)^3 = 0.1(9)(-8) = -7.2$ So, the point is $(1, -7.2)$.

6. For $x = 2$: [ h(2) = 0.1(2 + 2)^2(2 - 3)^3 =