Math Problem Statement

How do you graph the function h(x)=x2−3x+5h(x)=x2−3x+5 and identify key points?

Solution

To graph the function h(x)=x23x+5h(x) = x^2 - 3x + 5, you can follow these steps:

1. Identify the form of the function:

The given function h(x)=x23x+5h(x) = x^2 - 3x + 5 is a quadratic function of the form ax2+bx+cax^2 + bx + c, where a=1a = 1, b=3b = -3, and c=5c = 5. The graph of a quadratic function is a parabola.

2. Find the vertex:

The vertex of a parabola in the form ax2+bx+cax^2 + bx + c can be found using the formula for the x-coordinate of the vertex: xv=b2a=(3)2(1)=32=1.5x_v = \frac{-b}{2a} = \frac{-(-3)}{2(1)} = \frac{3}{2} = 1.5

Now, substitute xv=1.5x_v = 1.5 into the original equation to find the y-coordinate of the vertex: h(1.5)=(1.5)23(1.5)+5=2.254.5+5=2.75h(1.5) = (1.5)^2 - 3(1.5) + 5 = 2.25 - 4.5 + 5 = 2.75 So, the vertex is (1.5,2.75)(1.5, 2.75).

3. Determine the axis of symmetry:

The axis of symmetry is the vertical line that passes through the vertex. The equation of the axis of symmetry is: x=1.5x = 1.5

4. Find the y-intercept:

To find the y-intercept, set x=0x = 0 in the function: h(0)=023(0)+5=5h(0) = 0^2 - 3(0) + 5 = 5 So, the y-intercept is (0,5)(0, 5).

5. Find additional points:

You can find other points on the graph by selecting values of xx around the vertex and calculating the corresponding yy-values.

  • For x=0x = 0, h(0)=5h(0) = 5
  • For x=1x = 1, h(1)=123(1)+5=3h(1) = 1^2 - 3(1) + 5 = 3
  • For x=2x = 2, h(2)=223(2)+5=3h(2) = 2^2 - 3(2) + 5 = 3

6. Determine the direction of the parabola:

Since the coefficient of x2x^2 (i.e., a=1a = 1) is positive, the parabola opens upwards.

7. Plot the points and sketch the graph:

Now that you have the vertex (1.5,2.75)(1.5, 2.75), the y-intercept (0,5)(0, 5), and additional points (1,3)(1, 3) and (2,3)(2, 3), you can plot these points and draw the parabola.

Key Points:

  • Vertex: (1.5,2.75)(1.5, 2.75)
  • Y-intercept: (0,5)(0, 5)
  • Symmetry: About the line x=1.5x = 1.5
  • Direction: Opens upwards

Would you like more details on any part of this explanation?


Here are 5 related questions to explore further:

  1. How do you find the x-intercepts of a quadratic function?
  2. What is the significance of the discriminant in a quadratic equation?
  3. How do you shift and scale a parabola by changing the coefficients of a quadratic equation?
  4. How do you find the maximum or minimum value of a quadratic function?
  5. How can you use factoring or the quadratic formula to solve x23x+5=0x^2 - 3x + 5 = 0?

Tip: If you're not sure where a quadratic opens up or down, always check the sign of the x2x^2 term—positive means upwards, negative means downwards.

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Math Problem Analysis

Mathematical Concepts

Quadratic Functions
Graphing
Vertex Form
Symmetry
Parabolas

Formulas

Standard form of a quadratic function: ax^2 + bx + c
Vertex formula: x_v = -b / (2a)
Y-intercept: Set x = 0 in the function

Theorems

Symmetry of a parabola about the vertex
Quadratic function opens up if a > 0

Suitable Grade Level

Grades 9-11