Math Problem Statement

Problem 1 This problem focuses on the function f defined by Equation (1):

f(z) = 2 z 2 " 1 (1 − z 2 ) −1/2 − 1

  • 0#−1 . (1) (1.1) Plot f(z) only for values of z in the interval where 0 < z < 10−7 . The interval where 0 < z < 10−7 must fill the horizontal axis of the plot. (1.2) Plot f(z) only for values of z in the interval where 0 < z < 10−15 . The interval where 0 < z < 10−15 must fill the horizontal axis of the plot.

Solution

Here are the plots for the function f(z)=2z2(1z2)121f(z) = 2z^2 \left(1 - z^2\right)^{-\frac{1}{2}} - 1:

  1. Plot for 0<z<1070 < z < 10^{-7} (left plot): The function is shown over this small interval, filling the horizontal axis.
  2. Plot for 0<z<10150 < z < 10^{-15} (right plot): This shows the function over an even smaller interval, as requested.

Let me know if you'd like a detailed explanation of the behavior of the function in these intervals or if you have other questions.

Here are five related questions to consider:

  1. What happens to the function f(z)f(z) as zz approaches zero?
  2. How does the behavior of f(z)f(z) change if we change the power in the denominator (1z2)1/2\left(1 - z^2\right)^{-1/2}?
  3. What would the function look like for negative values of zz?
  4. How does this function compare to simpler functions like z2z^2?
  5. How does the term (1z2)12\left(1 - z^2\right)^{-\frac{1}{2}} affect the overall behavior of f(z)f(z)?

Tip: Be cautious with very small intervals like 101510^{-15}, as the function can be numerically unstable near zero!

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Math Problem Analysis

Mathematical Concepts

Calculus
Plotting Functions
Limits
Asymptotic Behavior

Formulas

f(z) = 2z^2 (1 − z^2)^{-1/2} − 1
Asymptotic behavior as z → 0

Theorems

Limits and Continuity
Numerical Stability in Function Plotting

Suitable Grade Level

Undergraduate Level (Calculus or Mathematical Analysis)