Math Problem Statement
Solution
Let's go through the questions one by one from the image.
1) Kinematics in 1D
The first problem involves a car's motion along a straight line, given by the position function: where is in meters and is in seconds.
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(a) Position at : Substitute into the position function to find the car's position at that time.
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(b) Velocity at : The velocity is the first derivative of the position function, . Compute the derivative of and then substitute .
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(c) Acceleration: The acceleration is the second derivative of the position function, .
2) Analyzing velocity and acceleration from a graph
The second problem gives a velocity vs. time graph with two points: and . You're asked to determine:
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(a) Acceleration of : Acceleration is the slope of the velocity-time graph. Calculate the slope between the origin and .
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(b) Acceleration of : Find the slope of the line from the origin to .
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(c) Time when and meet: You need to determine when both lines have the same velocity.
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(d) Distance from the initial position when and meet: This can be found using the area under the velocity-time graph.
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(e) Velocity when and meet: This is the velocity where the two lines intersect.
3) Projectile motion
The third problem is a projectile motion question, where a bullet is fired at a target 91.4 meters away with an initial velocity .
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(a) Find two possible angles ( and ): Use the given identity for projectile motion and solve for the angles that satisfy the range equation.
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(b) Time of flight: Determine the time required for the bullet to reach the target for both angles.
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Math Problem Analysis
Mathematical Concepts
Kinematics
Projectile Motion
Velocity-Time Graph
Derivatives
Formulas
x(t) = 5t^2 + 2t + 1
v(t) = dx(t)/dt
a(t) = d^2x(t)/dt^2
Range equation for projectile motion
2sin(θ)cos(θ) = sin(2θ)
Theorems
Kinematic Equations of Motion
Slope of velocity-time graph gives acceleration
Projectile motion range equation
Suitable Grade Level
Undergraduate Physics (First Year)
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