Math Problem Statement

Physics Problems related to Kinematics in 1D and 2D: Analyze car motion, velocity vs time graph, and projectile motion.

Solution

Let's go through the questions one by one from the image.

1) Kinematics in 1D

The first problem involves a car's motion along a straight line, given by the position function: x(t)=5t2+2t+1x(t) = 5t^2 + 2t + 1 where xx is in meters and tt is in seconds.

  • (a) Position at t=3t = 3: Substitute t=3t = 3 into the position function to find the car's position at that time.

  • (b) Velocity at t=3t = 3: The velocity is the first derivative of the position function, v(t)=dx(t)dtv(t) = \frac{dx(t)}{dt}. Compute the derivative of x(t)x(t) and then substitute t=3t = 3.

  • (c) Acceleration: The acceleration is the second derivative of the position function, a(t)=d2x(t)dt2a(t) = \frac{d^2x(t)}{dt^2}.

2) Analyzing velocity and acceleration from a graph

The second problem gives a velocity vs. time graph with two points: QQ and PP. You're asked to determine:

  • (a) Acceleration of QQ: Acceleration is the slope of the velocity-time graph. Calculate the slope between the origin and QQ.

  • (b) Acceleration of PP: Find the slope of the line from the origin to PP.

  • (c) Time when PP and QQ meet: You need to determine when both lines have the same velocity.

  • (d) Distance from the initial position when PP and QQ meet: This can be found using the area under the velocity-time graph.

  • (e) Velocity when PP and QQ meet: This is the velocity where the two lines intersect.

3) Projectile motion

The third problem is a projectile motion question, where a bullet is fired at a target 91.4 meters away with an initial velocity v0=427m/sv_0 = 427 \, \text{m/s}.

  • (a) Find two possible angles (θ1\theta_1 and θ2\theta_2): Use the given identity for projectile motion and solve for the angles that satisfy the range equation.

  • (b) Time of flight: Determine the time required for the bullet to reach the target for both angles.

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Math Problem Analysis

Mathematical Concepts

Kinematics
Projectile Motion
Velocity-Time Graph
Derivatives

Formulas

x(t) = 5t^2 + 2t + 1
v(t) = dx(t)/dt
a(t) = d^2x(t)/dt^2
Range equation for projectile motion
2sin(θ)cos(θ) = sin(2θ)

Theorems

Kinematic Equations of Motion
Slope of velocity-time graph gives acceleration
Projectile motion range equation

Suitable Grade Level

Undergraduate Physics (First Year)