To find the perimeter of the triangle formed by points A(-4, 3), B(3, 3), and C(-2, -3), we will first calculate the lengths of the three sides of the triangle using the distance formula:

The distance between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by:

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Step 1: Find the distance between A and B

$A(-4, 3), B(3, 3)$ $AB = \sqrt{(3 - (-4))^2 + (3 - 3)^2} = \sqrt{(3 + 4)^2 + 0^2} = \sqrt{7^2} = 7$

Step 2: Find the distance between B and C

$B(3, 3), C(-2, -3)$ $BC = \sqrt{(-2 - 3)^2 + (-3 - 3)^2} = \sqrt{(-5)^2 + (-6)^2} = \sqrt{25 + 36} = \sqrt{61} \approx 7.81$

Step 3: Find the distance between A and C

$A(-4, 3), C(-2, -3)$ $AC = \sqrt{(-2 - (-4))^2 + (-3 - 3)^2} = \sqrt{(2)^2 + (-6)^2} = \sqrt{4 + 36} = \sqrt{40} \approx 6.32$

Step 4: Find the perimeter

Now, sum the lengths of the sides: $\text{Perimeter} = AB + BC + AC = 7 + 7.81 + 6.32 = 21.13$

Thus, the perimeter is approximately 21.1.

The correct answer is 21.1.

Let me know if you'd like further details or have any questions!

Here are some related questions you might find interesting:

1. How does the distance formula apply to 3-dimensional coordinates?
2. What would be the perimeter of a quadrilateral if given its vertices?
3. How can you determine if a triangle is right-angled using distance formulas?
4. How do you calculate the area of a triangle given its vertices?
5. What is the significance of the Pythagorean theorem in triangle perimeter calculations?

Tip: When calculating the perimeter of a polygon, always ensure you apply the distance formula between each consecutive pair of points and then sum the lengths!