The problem states that 12% of students in a class are left-handed, and the rest are right-handed. Let's solve it step by step:

Step 1: Convert Percentage to Fraction

Since 12% = 12/100, we simplify:

$\frac{12}{100} = \frac{3}{25}$

Thus, the fraction of students who are left-handed is 3/25.

Step 2: Find the Fraction of Right-Handed Students

Since the total percentage is 100%, the right-handed students make up:

$100\% - 12\% = 88\%$

Converting this to a fraction:

$\frac{88}{100} = \frac{22}{25}$

Thus, the fraction of students who are right-handed is 22/25.

Step 3: Compare Left-Handed and Right-Handed Students

Since 22/25 is greater than 3/25, there are more right-handed students than left-handed students.

Would you like a more detailed breakdown of any step?

Here are some related questions:

1. If there are 50 students in the class, how many are left-handed?
2. What is the ratio of right-handed to left-handed students?
3. If 5 new left-handed students join, what fraction will now be left-handed?
4. How many more right-handed students are there than left-handed students in a class of 100?
5. What percentage of students are right-handed in decimal form?

Tip: When dealing with percentages, always convert them into fractions or decimals for easier calculations.